Answer:
Graph 4
Step-by-step explanation:
The graph of f(x) = x^3 includes point (0, 0) since f(0) = 0^3 = 0.
The exponent of x is 3. This is not a linear function.
Negative values of x cubed are negative, and positive values of x cubed are positive.
For x < 0, f(x) < 0, and for x > 0, f(x) > 0.
Answer: Graph 4.
5 is you answer because absolute value is the distance on a number line from 0
First calculate the function of x-2y=6:
x-2y=6 | - x
-2y=6-x | ÷ (-2)
y=0.5x-3
Now you have the function. Because the slope you search is parallel to this one, the slope is the same (in this case 0.5). A slope of 0.5 means for 2 steps to the right go one up. To define the function you are searching you have to find out the y intercept. For this take your point (-2|4). Now go as many steps to the right until you reach the y intercept or x=0 in this case you need 2 steps. So for 2 steps right you go one up. Now you have the y intercept (5).
The resulting function is: f(x) = 0.5+6.
I'm not for sure but I think the answer is maybe C.I hope this is correct
Hello,
f(0)=(0-6)(0-2)=12
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