If a = first term and r = common ratio we have
a + ar + ar^2 = 13 and ar^2 / a = r^2 = 9
so r = 3
and a + 3a + 9a = 13
so a = 1
so they are 1,3 and 9
2.
in geometric series we have
4 , 4r ,4r^2 , 60
Arithmetic;
4, 4r , 4r + d , 4r + 2d
so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30
so d = 30 - 2r
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0
2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24
and the numbers are 4*3 = 12 , 4*3^2 = 36
first 3 are 4 , 12 and 36 ( in geometric)
and last 3 are 12, 36 and 60 ( in arithmetic)
The 2 numbers we ause are 12 and 36.
Answer:
Jamal will have made 12 more T-shirts than Sean on the 6th day.
Step-by-step explanation:
1 day for Jamal - 6 T-shirts. 1 day for Sean - 4 T-shirts. 2 day for Jamal - 12 T-shirts. 2 day for Sean - 8 T-shirts. 3 day for Jamal - 18 T-shirts. 3 day for Sean - 12 T-shirts. 4 day for Jamal - 24 T-shirts. 4 day for Sean - 16 T-shirts. 5 day for Jamal - 30 T-shirts. 5 day for Sean - 20 T-shirts. 6 day for Jamal - 36 T-shirts. 6 day for Sean - 24 T-shirts. Number between 24 and 36 = 12.
1 7/11 = 18/11
2 5/6 = 17/6
Product = 18/11 * 17/6
= 306 / 66 = 51/11 = 4 7/11 Answer
