Answer:
-2
Step-by-step explanation:
Answer: his overall GPA will be 2.93, which means he doesn't pass out with a 3.0 GPA
Step-by-step explanation:
GPA = 2.78
total credit hour = 105
Total credit unit = 105 x 2.78 = 291.9
If he takes a 15 credit hour and gets a perfect 4.0 GPA,
his total credit unit = 15 x 4 = 60
Final GPA = (291.9 + 60)/(105 + 15)
= 351.9/120 = 2.93
<h2> ☞ANSWER☜</h2>
<u> </u><u>2</u><u>3</u><u>0</u><u>FT</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u>Regular tetrahedron</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>Solve for volume</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>V≈1.15×107</u>
<u>Use the formula for the volume of a triangular pyramid: V=13Ah , where A = area of the triangular base, and H = height of the pyramid.</u>
Answer:
hbb
2
Step-by-step explanation:
Answer:
LHS of the given equation is:
sinθ+sin3θ+sin5θ+sin7θ=(sinθ+sin7θ)+(sin3θ+sin5θ)=2sin8θ2.cos6θ2+2sin8θ2.cos2θ2 [since sinC+sinD=2sinC+D2.cosC−D2=2sin4θ.cos3θ+2sin4θ.cosθ=2sin4θ.[cos3θ+cosθ] [since cosC+cosD=2cosC+D2.cosC−D2=2sin4θ.[2cos2θ.cosθ]=4cosθ.cos2θ.sin4θsinθ+sin3θ+sin5θ+sin7θ=(sinθ+sin7θ)+(sin3θ+sin5θ)=2sin8θ2.cos6θ2+2sin8θ2.cos2θ2 [since sinC+sinD=2sinC+D2.cosC-D2=2sin4θ.cos3θ+2sin4θ.cosθ=2sin4θ.[cos3θ+cosθ] [since cosC+cosD=2cosC+D2.cosC-D2=2sin4θ.[2cos2θ.cosθ]=4cosθ.cos2θ.sin4θ
any more help just ask :)
Step-by-step explanation: