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guapka [62]
2 years ago
15

Find the area of the triangle

Mathematics
1 answer:
raketka [301]2 years ago
8 0
The area of the triangle is 253.5 yd^2
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Use the substitution method to solve the following system of equations: 3x + 5y = 3 x + 2y = 0 (1 point) (1, 1) (6, −3) (6, 1) (
PtichkaEL [24]

Step-by-step explanation:

Given.

3x+5y=3

x+2y=0

Take the second equation and subtract 2y to both sides.

(x+2y)-2y=0-2y

x=-2y

Substitute x into the first equation and simplify.

3x+5y=3

3(-2y)+5y=3

-6y+5y=3

-y=3

Invert.

y=-3

Substitute Y into your second equation.

x+2y=0

x+2(-3)=0

x-6=0

Add -6 to both sides.

(x-6)+6=0+6

x=6

Answer:

(6, -3)

6 0
3 years ago
Sila jogged 12 kilometers today and wants to know how far she traveled in feet. What error did Sila make while converting from k
ozzi

Answer:

umm i'm not rly sure what's going on here...but here's how i'd do it

Step-by-step explanation:

3280.84x12=39370.08 which is about 3,9370 feet.

to double check let's do an algebraic expression

1/3280.84=x/12        cross multiply

x(1)=3280.84(12)       simplify

x=39370.08

hope that helped.

8 0
3 years ago
Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
2 years ago
Find two positive numbers whose difference is 17 and whose product is 1410
Dafna11 [192]

Answer:

30 and 47

their difference is 17 and when multiplied equal 1410

4 0
3 years ago
How do you find perimeter
Veronika [31]
All you do is add up all your sides! So if your shape has 4+4+5+5 = 18. All you do is add them up! 
3 0
3 years ago
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