1: m=-4
2: b=-4
3: -9=k
4: C=-11.4
5:X<10
In order to reduce ANY fraction to lowest terms, find any common factors
of the numerator and denominator, and divide them both by it. If they still
have a common factor, then divide them by it again. Eventually, they won't
have any common factor except ' 1 ', and then you'll know that the fraction is
in lowest terms.
Do 15 and 40 have any common factors ?
Let's see . . .
The factors of 15 are 1, 3, <em>5</em>, and 15 .
The factors of 40 are 1, 2, 4,<em> 5</em>, 8, 10, 20, and 40 .
Ah hah ! Do you see that ' <em>5</em> ' on both lists ? That's a common factor.
So 15/40 is NOT in lowest terms.
Divide the numerator and denominator both by 5 :
15 / 40 =<em> 3 / 8</em>
3 and 8 don't have any common factor except ' 1 '.
So 3/8 is the same number as 15/40, but in lowest terms.
To solve this problem you use the "Triangle Inequality Theorem" it states that: any side of a triangle is always shorter than the sum of the other two sides.
Using this theorem we check each side
5+7=12: this is greater than the other side which is 11, so this works
11+7= 18: this is greater than the other side which is 5, so this works
5 + 11= 16: this is greater that the other side which is 7, so this works
Answer:
For any value of x (1) will always be greater than h(x).
For any value of x;h(t) will always be greater than g(x).
Step-by-step explanation:
