What table.
If it is a normal table or a wooden table. The marble ones are cool but I prefer the wood. btw this is just filler text so I could ask if you would link the table.
Point-slope form: y-y1 = m(x-x1)
Standard form: ax + by = c
Slope-intercept form: y = mx+b
Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.
To create point-slope form, we need to get one point from the graph. Let's use (3,0).
To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.
To get standard form, solve the equation in terms of C.
Point-slope form: y = -4/3(x-3)
Slope-intercept form: y = -4/3x + 4
Standard form: 4/3x + y = 4
Answer:
As for this problem, we will first establish that the length of the flower bed be represented as x, the width of the flower bed be represented as x/2 ,and the area of the flower bed be taken as it is since it is given. We then follow the formula for area which is length multiplied to width which is:
A = LW
we then substitute them
34 square feet = x (x/2)
now all we need to do is find x first.
34 square feet = x squared / 2
now do a cross multiplication
68 square feet = x squared
then get the square root of both sides
8.246 feet = x
Since x is equal to the length of the flower bed, all we have to do to get the width of it is to divide it by 2. So...
W = x/2
W = 8.246 feet / 2
W = 4.123 feet
And since the problem asked it to find the width of the flower bed to the nearest tenth of a foot, the answer would be 4.1 ft.
Answer:
<h3><em>
(12, -6)</em></h3>
Step-by-step explanation:
The formula for calculating the midpoint of two coordinates is expressed as shown;
M(X, Y) = [(x1+x2)/2, (y1+y2)/2]
Given the midpoint of ST to be ((6, -2) and one endpoint T is (0,2), according to expression above;
X = (x1+x2)/2
Y = (y1+y2)/2
From the coordinates, X = 6, Y = -2, x1 = 0 and y1 = 2, to get x2 and y2;
X = (x1+x2)/2
6 = (0+x2)/2
cross multiply
12 = 0+x2
x2 = 12-0
x2 = 12
For 2;
Y = (y1+y2)/2
-2 = (2+y2)/2
cross multiply
-4 = 2+y2
y2 = -4-2
y2 = -6
<em>Hence the other endpoint S(x2, y2) is (12, -6)</em>
<em></em>
I think this is right if not oh well but the domain of marcos mapping diagram is paired with exactly one element in the range.
