In the case above, the correct vectors are:
- <25.98, -15>.
- <1.71, 4.7>.
<h3>What is the ship vector about?</h3>
The solution for the Ship's vector are:
Note that the Horizontal aspect = 30 cos 30
= 25.98.
For the Vertical aspect = 30 sin(-30)
= -15.
Hence it will be <25.98, -15>.
In regards to the current's vector:
The Horizontal aspect= 5 sin 20
= 1.71.
The Vertical aspect = 5 cos 20
= 4.7.
Hence it will be <1.71, 4.7>.
Therefore, In the case above, the correct vectors are:
- <25.98, -15>.
- <1.71, 4.7>.
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Answer: 5+7=2x
Step-by-step explanation:
Answer:
The range would be {-4,-3,1,6}
Step-by-step explanation:
Individual points are bracketed
It would be the third one 7n=10-3n
Answer:
f(x) = 8x⁴-8x²+1
Step-by-step explanation:
I will assume that f(cos θ) = cos(4θ). Otherwise, f would not be a polynomial. lets divide cos(4θ) in an expression depending on cos(θ). We use this properties
- cos(2a) = cos²(a) - sin²(b)
- sin(2a) = 2sin(a)cos(a)
- sin²(a) = 1-cos²(a)
cos(4θ) = cos(2 * (2θ) ) = cos²(2θ) - sin²(2θ) = [ cos²(θ)-sin²(θ) ]² - [2cos(θ)sin(θ)]² = [cos²(θ) - ( 1 - cos²(θ) ) ]² - 4cos²(θ)sin²(θ) = [2cos²(θ)-1]² - 4cos²(θ) (1 - cos²(θ) ) = 4 cos⁴(θ) - 4 cos²(θ) + 1 - 4 cos²(θ) + 4 cos⁴(θ) = 8cos⁴(θ) - 8 cos²(θ) + 1
Thus f(cos(θ)) = 8 cos⁴(θ) - 8 cos²(θ) + 1, and, as a result
f(x) = 8x⁴-8x²+1.
