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3 years ago

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A small insurance company has determined that on average it receives 6 property damage claims per day. P left parenthesis X equa

ls k right parenthesis space equals space fraction numerator lambda to the power of k e to the power of negative lambda end exponent over denominator k factorial end fraction k space i s space t h e space g i v e n space n u m b e r space o f space e v e n t space o c c u r r e n c e s lambda space i s space t h e space a v e r a g e space r a t e space o f space e v e n t space o c c u r r e n c e s What is the probability that the company will receive 7 property damage claims on a randomly selected day? Answer choices are rounded to the hundredths place.

1 answer:

kakasveta [241]3 years ago

5 0

Answer:

Euclid introduced the axiomatic

Step-by-step explanation:

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If A={x|x is an odd integer} and B={9,11,12,14} list the elements of A n B. Please help ASAP!!!!!!! :( So find the intersection

azamat

An integer is simply all numbers (including the negative numbers) that are not fractions

The intersection would simply be all the odd numbers in Set B.

<u>The answer is (9,11)</u>

5 0

3 years ago

Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close parentheses plus open parentheses

emmasim [6.3K]

$\bf \cfrac{\sqrt{-16}}{(1+i)+(6+3i)}\implies \cfrac{\sqrt{-1\cdot 16}}{1+i+6+3i}\implies \cfrac{\sqrt{-1}\cdot \sqrt{16}}{7+4i}
\\\\\\
\cfrac{i\cdot \sqrt{4^2}}{7+4i}\implies \cfrac{4i}{7+4i}\impliedby 
\begin{array}{llll}
\textit{now, we'll multiply by the}\\
\textit{conjugate of the denominator}
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{and recall }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
\textit{also recall that }i^2=-1
\\\\
-------------------------------\\\\$

$\bf \cfrac{4i}{7+4i}\cdot \cfrac{7-4i}{7-4i}\implies \cfrac{4i(7-4i)}{(7+4i)(7-4i)}\implies \cfrac{28i-16i^2}{7^2-(4i)^2}
\\\\\\
\cfrac{28i-16(-1)}{49-(4^2i^2)}\implies \cfrac{28i+16}{49-[16(-1)]}\implies \cfrac{16+28i}{49+16}\implies \cfrac{16+28i}{65}
\\\\\\
\cfrac{16}{65}+\cfrac{28i}{65}$

5 0

4 years ago

Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)

masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

$y=ax^2+bx+c$ ...(i)

It is passes through the point (0,11). So, substitute $x=0,y=11$ in (i).

$11=a(0)^2+b(0)+c$

$11=c$

Putting $c=11$ in (i), we get

$y=ax^2+bx+11$ ...(ii)

The quadratic function passes through the point (5,31). So, substitute $x=5,y=31$ in (ii).

$31=a(5)^2+b(5)+11$

$31-11=a(25)+5b$

$20=25a+5b$

Divide both sides by 5.

$4=5a+b$ ...(iii)

The quadratic function passes through the point (3,11). So, substitute $x=3,y=11$ in (ii).

$11=a(3)^2+b(3)+11$

$11-11=a(9)+3b$

$0=9a+3b$

Divide both sides by 3.

$0=3a+b$ ...(iv)

Subtracting (iv) from (iii), we get

$4-0=5a+b-3a-b$

$4=2a$

$\dfrac{4}{2}=a$

$2=a$

Putting $a=2$ in (iv), we get

$0=3(2)+b$

$0=6+b$

$-6=b$

Putting $a=2,b=-6$ in (ii), we get

$y=(2)x^2+(-6)x+11$

$y=2x^2-6x+11$

Therefore, the required quadratic equation is $y=2x^2-6x+11$ .

7 0

3 years ago

Sam and you are going to paint your room together.

guapka [62]

Answer:

Sam is incorrect because you would not add the two times together. Hence there being 2 people working it would take you guys less time. You would actually subtract the times to get 5 minutes

Step-by-step explanation:

8 0

3 years ago

I need help but I need the correct answer everyone is giving me the wrong answer !!

Jlenok [28]

Answer:

y - 2 = 6 (x - 1)

Step-by-step explanation:

Slope intercept form equations look like this:

y - y1 = m (x - x1)

***m = $\frac{y2-y1}{x2-x1}$

Using the point (1,2), we know that x1 = 1 and y1 = 2. Let's sub these values into the slope intercept equation:

y - 2 = m (x - 1)

To complete this equation, we need to find slope. Pick out another point on the graph and plug into the slope equation. We can use point (2,8), where (1,2) = Point 1 and (2,8) = Point 2.

$\frac{y2-y1}{x2-x1}=\frac{8-2}{2-1} =\frac{6}{1} =6$

Now that we know m = 6, let's plug that back into the original equation to get our final answer:

<u>y - 2 = 6 (x - 1) </u>

I hope this helps!

6 0

2 years ago