The equation of the perpendicular line to the given line is: y = -5/4x - 30.
<h3>What is the Equation of Perpendicular Lines?</h3>
The slope values of two perpendicular lines are negative reciprocal of each other.
Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.
Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.
Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:
20 = -5/4(-40) + b
20 = 50 + b
20 - 50 = b
b = -30
Substitute m = -5/4 and b = -30 into y = mx + b:
y = -5/4x - 30
The equation of the perpendicular line is: y = -5/4x - 30.
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Answer: 
<u>Step-by-step explanation:</u>
To find the tangent, you need to find the derivative with respect to x.
Then substitute x = 1 into the derivative.
Given: 0 = 2x² - xy - y²
Derivative: 0 = 4x - y' - 2yy'
Solve for y': 2yy' + y' = 4x
y'(2y + 1) = 4x


Answer:
x = 3
Step-by-step explanation:
Let's solve your equation step-by-step.
5x + 11 = -3x +35
Add 3x to both sides.
5x + 11 + 3x = -3x + 35 + 3x
8x + 11 = 35
Subtract 11 from both sides.
8x + 11 - 11 = 35 - 11
8x = 24
Divide both sides by 8.

x = 3
So therefore, that is how you found your answer: x = 3
3 divided by (4 + n). Hope it helps! :)