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maxonik [38]
3 years ago
7

Given: △CGF ,CG=GF=CF=and, KOPS is a square inside this triangle with one side on CF and its two vertices on CG and GF

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

  AKPOS/ACGF = 28√3 -48 ≈ 0.497423

Step-by-step explanation:

Let's assume the square is a unit square. Then the height of the triangle is ...

  1 +(√3)/2 = h

and half the base of the triangle is ...

  h/√3 = (√3)/3 +1/2 = b/2

The area of the triangle is the product of these:

  A = (1/2)bh

  = (2 +√3)/2 × (3 +2√3)/6

  = (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12

So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...

  (square area)/(triangle area) = 12/(12+7√3)

  (square area)/(triangle area) = 28√3 -48

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zmey [24]

The domain of the function is x > 0 and the range of the function is -∞ < f(x) < ∞

<h3>How to determine the domain?</h3>

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