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3 years ago

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Rosa is 13 years old and 6 months old and her brother Malcolm is 11 and 6 months old. Their great grandfather is 89 years old. H

ow many years older is the great grandfather then the combined ages of Rosa and Malcolm?

1 answer:

ryzh [129]3 years ago

4 0

Answer:

64 years older.

Step-by-step explanation:

13.5+11.5=25

89-25=64.

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Hideki throws a baseball ball upward with an initial velocity of 12 meters/sec. When he throws the ball, it is two meters above

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For this case we have the following kinematic equation that models the problem:
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Rewriting we have:
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When the ball hits the ground we have:
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We ignore the negative root because it is time.
Answer:
It will take the ball to hit the ground about:
t = 2.61 sec

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Answer:

x ≈ {-1.8, 0.5}

Step-by-step explanation:

I find a graphing calculator to be about the easiest way to solve these. It is convenient to put the equation into the form f(x) = 0. Here we can do that by subtracting 3x^2 from both sides.

9x^2 +8x -5 = 3x^2 . . . . . given

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A cafeteria serves 120 pints of milk each day. How many quarts of milk does the cafeteria serve each def

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Step-by-step explanation:

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<h2><u>Given</u><u>:</u><u>-</u></h2>

${ \large{➢ \: \: \bf{x = - 8}}}$

<h2><u>Solution</u><u>:</u><u>-</u></h2>

${ \large{➢ \: \: \bf{ \dfrac{2y}{3} = 3 \times - 8 + 34}}}$

${ \large{➢ \: \: \bf{ \dfrac{2y}{3} = - 24 + 34}}}$

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3 years ago

A certain system can experience three different types of defects. Let Ai (i = 1,2,3) denote the event that the system has a defe

andreev551 [17]

Answer:

(a) 0.5000

(b) 0.0833

(c) 0.2500

((d) 0.9500

Step-by-step explanation:

Given that the following probabilities;

P(A1) = 0.12; P(A2) = 0.08,

P(A3) = 0.05; P(A1 ∪ A2) = 0.14, P(A1 ∪ A3) = 0.14,

P(A2 ∪ A3) = 0.11,

P(A1 ∩ A2 ∩ A3) = 0.01

(a) we want to find P(A2/A1).

P(A2/A1) = P(A1nA2)/P(A1)..........a

So we need to find P(A1nA2)

P(A1 ∪ A2)= P(A1) + P(A2) - P(A1nA2)

P(A1nA2) =P(A1) + P(A2) - P(A1 ∪ A2)

P(A1nA2) = 0.12 + 0.08 - 0.14

P(A1nA2) = 0.20- 0.14

P(A1nA2 )= 0.060

P(A2/A1) = 0.06/0.12

= 0.5000. (Ans)

(b) The required probability is: P(A2∩A3/A1) =[P(A2∩A3)∩P(A1)] /P(A1).........b

But [P(A2nA3)nP(A1)] = P(A1∩A2∩ A3)

P(A2∩A3/A1) = 0.01/0.12

P(A2∩A3/A1) = 0.0833 (Ans)

(c) the required probability is given by Pr =

(Pr. of A1 defect) + (Pr. of A2 defect) + (Pr. of A3 defect)........c

Pr = 0.12 + 0.08 + 0.05

Pr = 0.2500 (And)

(d) The required probability is given by:

Pr[(A3)' /(A1∩A2)] = Pr[(A3)'nPr(A1∩A2)] /Pr(A1∩A2)]

Pr(A3)’ = 1 - Pr(A3) = 1 -0.05

Pr(A3)'/(A1∩A2)= (0.95×0.06)/(0.06)

Pr(A3)'/(A1∩A2 )= 0.95(Ans)......d

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3 years ago