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mixer [17]
3 years ago
7

Hey! i’ll give brainliest help thanks

Mathematics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

its A

Step-by-step explanation:

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How many numbers between 100 and 200 have 11 as a factor
Minchanka [31]

Answer:

101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199.

Step-by-step explanation:

6 0
3 years ago
What is the measure of AC?
OleMash [197]
The measure of AC is 10 I’m pretty sure
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3 years ago
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If DF = 61 and EF = 18, find DE
vova2212 [387]

Answer:

43 i jus subtracted

Step-by-step explanation:

5 0
3 years ago
An animal that has body parts that are arranged around a central point has
sammy [17]
Radically symmetrical
8 0
3 years ago
One-hour carbon monoxide concentrations in 43 air samples from a section of a city showed an average of 11.6 ppm and a standard
DENIUS [597]
The test statistic for difference between two means is given by:

z= \frac{(\bar{x}_1-\bar{x}_2)-(\mu_1-\mu_2)}{ \sqrt{ \frac{\sigma^2_1}{n_1} +\frac{\sigma^2_2}{n_2}} }

Thus, the appropriate test statistic is given by:

z= \frac{(11.6-6.4)-2}{ \sqrt{ \frac{(7.08)^2}{43} +\frac{(6.94)^2}{19}} } \\  \\ = \frac{5.2-2}{ \sqrt{ \frac{50.1264}{43} + \frac{48.1636}{19} } } = \frac{3.2}{ \sqrt{1.1657+2.5349} }  \\  \\ = \frac{3.2}{ \sqrt{3.7007} }  = \frac{3.2}{1.9237} =1.66

At 10% level of significance, the rejection region is given by

z\geq z_0

where: z_0 for 10% level of significance is 1.65

Since z = 1.66 > z_0=1.65, we reject the null hypothesis, which means that <span>the traffic control strategy does not reduce carbon monoxide concentrations by at least 2 ppm.</span>
3 0
3 years ago
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