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hram777 [196]
3 years ago
7

How long does it take for the ball to hit the ground (in seconds) rounded to the nearest hundredth

Mathematics
2 answers:
Fofino [41]3 years ago
8 0

Answer:

I need some numbers to do this problem

Step-by-step explanation:

Mars2501 [29]3 years ago
5 0

Answer:

Depends on the height of the ball and I don’t see that

Step-by-step explanation:

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SO CONFUSED PLEASE SOMEONE EXPLAIN! DUE SOON AND NEED HELP!!!!!!!! QUESTION IN PICTURE BELOW
jeka57 [31]

Answer:

=> Apply law of cosine

c^2=a^2+b^2-2abcos\left(C\right)

=> input value

z^2=6.5^2 + 9.4^2-\left(6.5\right)\left(9.4\right)\left(cos\left(131\right)\right)

=> simplify

z=\sqrt{\left(6.5^2+\:9.4^2\right)-\left(6.5\right)\left(9.4\right)\left(-0.65605902899\right)}

=> calulcation

z=\sqrt{-61.1\cos \left(131^{\circ \:}\right)+130.61},\:z=-\sqrt{-61.1\cos \left(131^{\circ \:}\right)+130.61}

=> apply rule: Distance must be greater than 0

which is about 14.51828

4 0
2 years ago
I have a question about fractions ​
yarga [219]

Answer:

please just add the question

5 0
2 years ago
Read 2 more answers
Is 3/10 greater than or less than 1/2
V125BC [204]
To compare two fraction we have to make common denominator, then we can compare numerators.
Lets do this
\frac{1}{2}= \frac{1*5}{2*5}= \frac{5}{10}
Now we can compare numeratos.
3<5, so 1/2 is greater than 3/10.
8 0
3 years ago
Read 2 more answers
In May you used 900 ​kilowatt-hours of energy for electricity.
Sloan [31]

Answer:

a) "The total electrical energy use was 3,240,000,000 joules."

b) "The average power use is 1210 watts."

c)

<u>Part 1:</u> "To generate the electricity you​ used, 810 L is needed."

<u>Part 2:</u> "To generate the electricity you​ used, 214.00 gal is needed."

Step-by-step explanation:

a)

1 kilowatt-hours = 3.6x10^6 joules

Converting 900 kilowatt-hours to joules, we have:

900*(3.6*10^6)=3.24*10^9 joules, or

Total Electrical Energy use = 3,240,000,000 joules

"The total electrical energy use was 3,240,000,000 joules."

b)

The month of May has 31 days and 1 day  is 24 hours. So May has:

31*24=744 hours

Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:

\frac{900}{744}=1.21 kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

1.21 * 1000 = 1210 Watts

"The average power use is 1210 watts."

c)

<u>Part 1:</u>

The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:

(3.24 * 10^9)*3 = 9.72 * 10^9 joules

We divide this by 12 million joules to get the number of liters:

\frac{9.72*10^9}{12*10^6}=810

So, 810 liters is needed

"To generate the electricity you​ used, 810 L is needed."

<u>Part 2:</u>

We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:

810 * 0.2642 = 214.00 gallons

"To generate the electricity you​ used, 214.00 gal is needed."

7 0
3 years ago
Can yall help me with the problem ?!
timurjin [86]
If I’m correct then it is 0.25
4 0
2 years ago
Read 2 more answers
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