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Scilla [17]
3 years ago
11

Help please i only have 3 min to finish

Mathematics
2 answers:
Elodia [21]3 years ago
6 0
Solve it is 1.7 + x -14
=12.3
Romashka [77]3 years ago
3 0

Answer: <u><em>I think that the answer should be 2.4</em></u>

<u><em /></u>

Step-by-step explanation: <em><u>The reason why is because they did 2 the 2.2 so their going up by twos I belive making the answer 2.4.</u></em>

You might be interested in
Solve inequality: -6x &lt; 36
7nadin3 [17]

Answer:

x>−6

Step-by-step explanation:

-6x<36

Multiply both sides by -1. ( reverse the inequality )

(-6x) (-1) > 36 (-1)

Simplify

6x > -36

Divide both sides by 6

6x divided by 6        -36 divided by 6

Simplify

x> -6

Hope this helped

6 0
3 years ago
-92 + -68 ? pls hurry !
Bezzdna [24]

Answer:

its -160

Step-by-step explanation:

:)

7 0
3 years ago
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

4 0
3 years ago
If pentagon OPQRS is dilated by a scale factor of seven over four from the origin to create O'P'Q'R'S', what is the ordered pair
Mariulka [41]

Answer:

The ordered pair of P'=(-8.75, 5.25)

Step-by-step explanation:

To get the ordered pair of point P' you simply have to multiply the coordinates of P by scale factor of 7/4

P:(-5,3)

P'(x,y)= (-5* 7/4, 3*7/4)

P'(x,y) = (-35/4 , 21/4)

P'(x,y) = (-8.75, 5.25)..

Thus the ordered pair of P'=(-8.75, 5.25)....

5 0
3 years ago
What is the product of 4^4(4^-7)(4)?<br> A. 1/-16<br> B. 1/-8<br> C. 1/16<br> D. 1/8
DIA [1.3K]

Answer:

C

Step-by-step explanation:

i used a calculator multiple times :)

8 0
3 years ago
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