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3 years ago

What is one symbol that is in algebra

Mathematics

2 answers:

daser333 [38]3 years ago

7 0

+,-,=,>,<, and many more, lol i gave more than one :P

S_A_V [24]3 years ago

5 0

+, (, ), -, •, =; and many, many, more!

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Using either the critical value rule or the p-value rule, if a one-sided null hypothesis for a single mean cannot be rejected at

KiRa [710]

Answer:

Step-by-step explanation:

Using either the critical value rule or the p-value rule, a conclusion can be drawn at a level of significance (alpha)

The null hypothesis: u = hypothesized mean

Alternative hypothesis: u > u0 or u < u0 for a one tailed test

Alternative hypothesis for a two tailed test: u =/ u0

To draw a conclusion by failing to reject the null hypothesis as stated then: using critical value

Observed z score > critical z score for both the one and two tailed test.

Or using p value:

P-value > alpha for a one tailed test

P-value > alpha/2 for a two tailed test

Thus, if a one-sided null hypothesis for a single mean cannot be rejected at a given significance level, then the corresponding two-sided null hypothesis will also not be rejected at the same significance level.

8 0

3 years ago

HELP PLZ I DON'T UNDERTSTAND IT

nasty-shy [4]

Answer:

The answer is A.

Step-by-step explanation:

Keeping point y as a reference, we know that it was rotated 180 degrees around the origin. I could tell this because y moved from one corner to another, if it was rotated 90 degrees it would move in a different direction. We also know it moved clockwise because if it moved counter clockwise it would have a different location.

We also know that it was shifted across the x-axis because it moved to the right. If it moved downwards it would have moved in the y direction.

Hope this helps.

8 0

3 years ago

Read 2 more answers

Our school's girls volleyball team has 14 players, including a set of 3 triplets: Missy, Lauren, and Liz. In how many ways can w

Sonja [21]

A - not all 3 triplets can be in the starting lineup

A' - all 3 triplets can be in the starting lineup

$\displaystyle |\Omega|=\binom{14}{6}=\dfrac{14!}{6!8!}=\dfrac{9\cdot10\cdot11\cdot12\cdot13 \cdot14}{2\cdot3\cdot4\cdot5\cdot6}=3003\\ |A'|=\binom{11}{3}=\dfrac{11!}{3!8!}=\dfrac{9\cdot10\cdot11}{2\cdot3}=165\\ |A|=3003-165=2838\\\\ P(A)=\dfrac{2838}{3003}=\dfrac{86}{91}\approx95\%$

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4 years ago

a tourist information center charges $10 per hour to rent a bicycle. is the rental charge proportional to the number of hours yo

PSYCHO15rus [73]

Yes they are because it is a constant rate of 10:1

8 0

4 years ago

Read 2 more answers

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago