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fomenos
3 years ago
13

Using the same spinner and die from the problem above, what is the probability of not spinning a blue, and then not rolling a fi

ve?
Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0
This is the answer to your question

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Workers on the assembly line produce 4x + 6 boats each day. Which expression shows how many boats they produced in 12 days?
Annette [7]
We're going to assume that x = # of days.
Plug 12 in as x:
4 × 12 = 48
48 + 6 = 54
They produced 54 boats in 12 days.
7 0
3 years ago
Read 2 more answers
What is the Range of this Graph? ASAP
Flura [38]

Answer:

The range would be {-4,-3,1,6}

Step-by-step explanation:

Individual points are bracketed

6 0
3 years ago
Solve 2x^2 + x - 4 = 0 <br> X2 +
damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
Solve for x.
gavmur [86]

7 \times 9 + x = 84 \\ 63 + x = 84 \\ x = 21

Answer is C.

Hope this helps. - M
8 0
3 years ago
Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
jeka94

by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression  x2 + 20 = 2x or , x^2 + 20 = 2x .

We know that Quadratic formula is :

x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

x^2 + 20 = 2x

⇒ x^2-2x+20=0

a=1\\b=-2\\c=20

Putting this value in equation x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} :

⇒ x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

⇒ x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}

⇒ x = \frac{2 \pm \sqrt{4-80}}{2}

⇒ x = (\frac{2 \pm 2i\sqrt{19}}{2})

⇒ x = 1 \pm (1)i\sqrt{19}}

Therefore , by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

7 0
3 years ago
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