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3 years ago

13

Using the same spinner and die from the problem above, what is the probability of not spinning a blue, and then not rolling a fi

ve?

1 answer:

MatroZZZ [7]3 years ago

4 0

This is the answer to your question

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A calculator screen displays 9.837E8. Write this number in standard form.

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Can someone please help I can’t understanddd.

dem82 [27]

Hello,

Dividing by 0 is not defined so let s take x different from 4 and -4 and then we can write:

As

$f(x)=x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)\\ \\(f\times g)(x)=\dfrac{3(x-4)(x-3)}{(x-4)(x+4)}=\dfrac{3x-9}{x+4}$

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3 years ago

The question is:

saul85 [17]

$f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1$

$(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\ \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a$

Therefore, $(fof^{-1})(a) = (f^{-1}of)(a) = a$

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3 years ago