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Rudiy27
1 year ago
14

Find the area of AAOB 9√3 un² 3√3 un² 4.5√3 un

Mathematics
1 answer:
butalik [34]1 year ago
7 0

Answer:

Step-by-step explanation:

The area of the equilateral triangle is \frac{\sqrt{3}}{4}(6)^{2}=\boxed{9\sqrt{3}}

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3⁵.2⁴.2¹.3⁶.(3²)⁴ and down (2³)².3⁶​<br>​
BARSIC [14]

Answer:

\dfrac{3^{13}}{2}

Step-by-step explanation:

Given expression:

\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}

\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:

\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies 3^{(19-6)} \cdot 2^{(5-6)}

\implies 3^{13} \cdot 2^{-1}

\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:

\implies \dfrac{3^{13}}{2^1}

\textsf{Apply exponent rule} \quad a^1=a:

\implies \dfrac{3^{13}}{2}

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On a scale drawing with a scale of 1 to 25 feet, the height of the building is 8 inches on a drawing. How tall is the actual bui
Wewaii [24]

Answer:

200 feet

Step-by-step explanation:

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Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y
kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

substitute in the formula

d=\sqrt{(5-2)^{2}+(2-0)^{2}}

d=\sqrt{(3)^{2}+(2)^{2}}

dAB=\sqrt{13}\ units

step 2

Find the distance BC

substitute in the formula

d=\sqrt{(7-5)^{2}+(-1-2)^{2}}

d=\sqrt{(2)^{2}+(-3)^{2}}

dBC=\sqrt{13}\ units

step 3

Find the distance AC

substitute in the formula

d=\sqrt{(7-2)^{2}+(-1-0)^{2}}

d=\sqrt{(5)^{2}+(-1)^{2}}

dAC=\sqrt{26}\ units

step 4

Compare the length sides

dAB=\sqrt{13}\ units

dBC=\sqrt{13}\ units

dAC=\sqrt{26}\ units

dAB=dBC

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

(AC)^{2} =(AB)^{2}+(BC)^{2}

substitute

(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}

26=13+13

26=26 -----> is true

therefore

Is an isosceles right triangle

8 0
3 years ago
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