Given:
A circle with center O, LN and MP are two diameters.
To find:
The minor arcs of the given circle.
Solution:
If any arc of a circle is less than its semicircle, then the arc is called is minor arc.
Since LN and MP are two diameters, therefore they divide the circle is two equal parts. So, the arc LN and arc MP are semicircles.
If arc LN and arc MP are the semicircles, then arc LM, arc MN, arc PL and arc NP are less than the semicircle.
So, arc LM, arc MN, arc PL and arc NP are minor arcs.
Therefore, the correct option is A.
