Question

Write the equation of the line that passes through the point (5, -6.5) and is perpendicular to the following equation:

Answer 1

Explanation:
first find the slope m of the line passing through the

the 2 given points
to calculate the slope m use the
gradient formula
∙
x
m
=
y
2
−
y
1
x
2
−
x
1
let
(
x
1
,
y
1
)
=
(
1
,
3
)
and
(
x
2
,
y
2
)
=
(
−
5
,
6
)
m
=
6
−
3
−
5
−
1
=
3
−
6
=
−
1
2
given a line with slope m then the slope of a line

perpendicular to it is
∙
x
m
perpendicular
=
−
1
m
hence
m
perpendicular
=
−
1
−
1
2
=
2
the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
here
m
=
2
y
=
2
x
+
b
←
is the partial equation
to find b substitute
(
−
2
,
7
)
into the partial equation
7
=
−
4
+
b
⇒
b
=
7
+
4
=
11
y
=
2
x
+
11
←
is the required equation