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tino4ka555 [31]
3 years ago
15

The four points (−2, 5), (−2, −1), (6, −1), and (3, 5) are the vertices of a polygon. What is the area, in square units, of this

polygon?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

39 square units

Step-by-step explanation:

crimeas [40]3 years ago
5 0
Look at the picture.

The polygon is a right-angled trapezoid.

The area is:
A=\frac{a+b}{2} \times h

The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.

A=\frac{8+5}{2} \times 6=\frac{13}{2} \times 6=13 \times 3=39

The area is 39 square units.

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Answer:

|(x-3)(x-11)|=0

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3 years ago
The CEO of a clothing company estimates that 52% of customers will make a purchase. Part A: How many customers should a salesper
4vir4ik [10]

Answer:

(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

Step-by-step explanation:

Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.

The probability that a customer makes a purchase is, <em>p</em> = 0.52.

The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.

The probability mass function of <em>X</em> is:

P(X=x)=(1-p)^{x}p

The expected value of a Geometric distribution is:

E(X)=\frac{1-p}{p}

(a)

Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:

E(X)=\frac{1-p}{p}

         =\frac{1-0.52}{0.52}\\=0.9231

This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b)

Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

P(X=3)=(1-0.52)^{3}\times0.52\\=0.110592\times 0.52\\=0.05750784\\\approx 0.058

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

8 0
3 years ago
The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.
finlep [7]

Answer:

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b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

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Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So,  1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

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(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

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