since AC is too short the answer would be
AC + CB < AB
Answer: E - S = (-16 and 6)
Step-by-step explanation:1/3 of the 30 decimals in T have an even tenths digit, it follows that 1/3*(30)=10 decimals in T have an even tenths digit.
Hence: Te =list of 10 decimals
Se = sum of all 10 decimals in Te
Ee =estimated sum of all 10 decimals in Te after rounding up.
Remaining 20 decimals in T all have an odd tenths digits.
To =list of this 20 decimals
So = sum of all 20 decimals in To
Eo = estimated sum of 20 decimals in To
Hence,
E = Ee + Eo and S =Se +So, hence:
E-S, =(Ee+Eo) - (Se+So) =(Ee-Se) +(Eo-So)
Ee-Se >10 (0.1)=1
S=10(1.8)+20(1.9) =18+38=56
E=10(2)+20(1)=40
E-S =40-56=-16.
AlsoS=10(1.2)+20(1.1)=34
E=10(2)+20(1)=40
E-S=40-34=6
Answer:
It is an irrational number, 
as a decimal rounded to the tenth place is 1.7
Step-by-step explanation:
All square roots are irrational numbers
Answer:
b............ .......... which one is a b c d
For this case we must indicate the graph of the following inequality:
y≥1−3x
It is observed that inequality includes equality, so the boundary line of the graph will not be dotted, so we discard options D and C.
We test option A, we substitute the point (0,0) in the inequality, if it is fulfilled then the graph corresponds to it.
We test option A, we substitute the point (0,0) in the inequality, if it is fulfilled then the graph corresponds to it.
It is not fulfilled
We test the last option B, we choose the point (3,1) that belongs to the graph:
1≥1−3(3)
\1≥1−9
1≥−8
it is fulfilled
