Answer:
any idea about the length of the box
Answer:
x=20
Step-by-step explanation:
The Pythagorean theorem is
a^2 +b^2 = c^2
where a and b are the legs and c is the hypotenuse.
The legs are x and 15 and the hypotenuse is 25
x^2 + 15^2 = 25^2
x^2 +225 = 625
Subtract 225 from each side
x^2 +225-225 = 625-225
x^2 = 400
Take the square root of each side
sqrt(x^2) = sqrt(400)
x = 20
A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.
Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).
D/13>-3
You have to multiply 13 in both sides to eliminate the Denominator 13 on the left leaving variable D only.
(D/13)(13) > -3(13)
D > -39
so... D. D > -39
