Please help me please will give brainliest to anyone who is right

Mathematics

2 answers:

dedylja [7]3 years ago

8 0

Answer:

Step-by-step explanation:

if you look at the graph the area thats purple for texas is farther up it meaning the tempature is higher.

rjkz [21]3 years ago

5 0

Answer:

A (?)

Step-by-step explanation:

You might be interested in

Solve the inequality -5(x-7)<15 algebraically for x.

Serggg [28]

X > 4
Hope this helps

6 0

3 years ago

Read 2 more answers

Explain how to determine if the triangle is an isosceles? Use algebraic formulas to SHOW

lorasvet [3.4K]

Answer: Hope This Helps!

Step-by-step explanation:

Use the distance formula to calculate the side length of each side of the triangle. If any 2 sides have equal side lengths, then the triangle is isosceles.

More precise info: Given the coordinates of the triangle's vertices, to prove that a triangle is an isosceles plot the 3 points (optional) use the distance formula to calculate the side length of each side of the triangle. If any 2 sides have equal side lengths, then the triangle is isosceles.

8 0

3 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$