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nekit [7.7K]
3 years ago
13

Solve the following problems for x.

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
5 0

3 (4x-7)+x

Solve!

here- first distribute then combine like terms then you will find your solution.

mario62 [17]3 years ago
4 0
The correct answer is : -84+x
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(2 to the power -1 ÷ 5 to the power- 1)2 × -5/8 to the power -1​
Luba_88 [7]

Answer:

-8

Step-by-step explanation

2 to the power of -1 = 0.5

5 to the power of -1 = 0.2

0.5/0.2 = 2.5

So,

(2.5)2 x -5/8 to the power of -1

-5/8 = -0.625

-0.625 to the power of -1 = -1.6

So,

(2.5)2 x -0.625

5 x -0.625

= -8

8 0
3 years ago
Read 2 more answers
Mark earns $12.25 an hour. How much did he make last week if he worked 25 hours?
serious [3.7K]

Answer:

306.25

Step-by-step explanation:

12.25(25)

8 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 y2 = (3x2 2y2 − x)2 (0,
inna [77]
X^2 + y^2 = (3x^2 + 2y^2 - x)^2
2x + 2y f'(x) = 2(3x^2 + 2y^2 - x)(6x + 4y f'(x) - 1) = 36x^3 + 24x^2yf'(x) + 24xy^2 + 16y^3f'(x) - 4y^2 - 18x^2 - 8xyf'(x) + x
f'(x)(2y - 24x^2y - 16y^3 + 8xy) = 36x^3 + 24xy^2 - 4y^2 - 18x^2 - x
f'(x) = (36x^3 + 24xy^2 - 4y^2 - 18x^2 - x)/(2y - 24x^2y - 16y^3 + 8xy)
f'(0, 0.5) = -4(0.5)^2/(2(0.5) - 16(0.5)^3) = -1/(1 - 2) = -1/-1 = 1

Let the required equation be y = mx + c; where y = 0.5, m = 1, x = 0
0.5 = 1(0) + c = 0 + c
c = 0.5

Therefore, the tangent line at point (0, 0.5) is
y = x + 0.5

3 0
3 years ago
Read 2 more answers
How do you turn 0.65 decimal into a fraction or mixed number into simplest form
Yakvenalex [24]
Put 65 over 100 so it's a fraction and simplify from there i think
5 0
4 years ago
Read 2 more answers
(07.03 LC)
Grace [21]

Answer:

B

Step-by-step explanation:

THis is a single equation with a single variable [y].

We can separate the variable in one side and the numbers to another and solve for y. Shown below:

3y + 4 = -2

3y = -2 - 4

3y = -6

y = -6/3

y = -2

THus, this equation has only 1 solution. B is correct

7 0
3 years ago
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