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Damm [24]
3 years ago
12

(07.03 LC)

Mathematics
1 answer:
Grace [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

THis is a single equation with a single variable [y].

We can separate the variable in one side and the numbers to another and solve for y. Shown below:

3y + 4 = -2

3y = -2 - 4

3y = -6

y = -6/3

y = -2

THus, this equation has only 1 solution. B is correct

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15=3(2x+4)-3 prove x=1
kherson [118]

Answer:

X=1

Step-by-step explanation:

6x+12-3=15

6x+9=15

6x+9-9=15-9

6x=6

X=1

4 0
3 years ago
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Which expressions can never result in a negative real number when evaluated for any value of x? Select all that apply.
DaniilM [7]
5 whshfunrkfnrj sjdbe
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Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral.
Nadusha1986 [10]

Here is a reference to the Inscribed Quadrilateral Conjecture it says that opposite angles of an inscribed quadrilateral are supplemental.

Explanation:

The conjecture, #angleA and angleC# allows us to write the following equation:

#angleA + angleC=180^@#

Substitute the equivalent expressions in terms of x:

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#angleC=88^@#

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4 0
3 years ago
If the original quantity is 10 and the new quantity is 11, what is the percent crease?
LenKa [72]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Help pls :(<br><br><br> Solve for x.<br> -4 + 3x = 20
prohojiy [21]

\huge\text{Hey there!}

\large\textsf{-4 + 3x = 20}\\\rightarrow\large\textsf{3x - 4 = 20}\\\\\large\text{ADD 4 to BOTH SIDES}\\\large\textsf{3x - 4 + 4 = 20 + 4}\\\large\text{CANCEL out: \textsf{-4 + 4} because that gives you \textsf 0}\\\large\text{KEEP: \textsf{20 + 4}} \text{ because it gives you the \textsf{x-value}}}\\\\\large\textsf{20 + 4 = \bf 24}\\\\\large\text{DIVIDE 3 to BOTH SIDES}\\\\\mathsf{\dfrac{3x}{3}= \dfrac{24}{3}}\\\large\text{CANCEL out: }\mathsf{\dfrac{3}{3}}\large\text{ because that gives you \textsf 1}

\large\text{KEEP: }\mathsf{\dfrac{24}{3}}\large\text{ because it helps gives you the result of the  \textsf{x-value}}\\\\\mathsf{x = \dfrac{24}{3}}\\\\\large\textsf{x= 24}\div \large\textsf{3}}\\\large\textsf{x = \bf 8}\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 8}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
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