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Dvinal [7]
3 years ago
13

151. Find the perimeter of this triangle

Mathematics
1 answer:
Lena [83]3 years ago
6 0

The perimeter is the sum of all the sides of the figure⇒

<em><u>151</u></em>

P=a+b+c+d...

P=(y+9)+(3y+3)+(4y+6)=y+9+3y+3+4y+6=8y+18

<u><em>152</em></u>

<u><em></em></u>P=a+b+c+d...\\P=(4a-100)+(2a-15)+(2a+40)=4a-100+2a-15+2a+40=\\=8a-75<u><em></em></u>

<u><em></em></u>

<u><em>153</em></u>

You forgot to attach a photo

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Answer:

(a)x=128 degrees

(b)\angle APD\neq 116^\circ

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\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ

(a) Now:

\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the  angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ

(b)

\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ

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