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OLEGan [10]
3 years ago
12

Sara has a rectangular garden in her backyard that measures 12 m by 15 m. She wants to put a rock walkway on the diagonal. How l

ong will the walkway be? Round to the nearest tenth of a meter
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

19.2 m

Step-by-step explanation:

Since this is a right triangle, we can use the pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

12^2 + 15^2 = c^2

144 + 225 = c^2

369 = c^2

Taking the square root of each side

sqrt(369) =sqrt(c^2)

19.20937271=c

To the nearest tenth

19.2 = c

valina [46]3 years ago
6 0

Answer:

Diagonal of rectangle walk = 19.2 meter (Approx.)

Step-by-step explanation:

Given:

Length of rectangle = 12 meter

Width of rectangle = 15 meter

Find:

Diagonal of rectangle walk

Computation:

Diagonal of rectangle = √l² + b²

Diagonal of rectangle walk = √Length of rectangle² + Width of rectangle²

Diagonal of rectangle walk = √12² + 15²

Diagonal of rectangle walk = √144 + 225

Diagonal of rectangle walk = √369

Diagonal of rectangle walk = 19.2093

Diagonal of rectangle walk = 19.2 meter (Approx.)

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Work Shown
Problem 21) 
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The three noncollinear points form a single plane. This is simply an axiom. 
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Problem 22) 
Original Conditional is in the form If P, then Q
The converse is the flip of that. So we go to If Q, then P.
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Problem 25) 
Angle DXE = 36 (given)
Angle CXD = angle DXE (definition of bisection)
Angle CXD = 36
Angle CXE = (angle CXD)+(angle DXE)
Angle CXE = 36+36
Angle CXE = 72
Angle BXE = 2*(angle CXE) ... since XC bisects angle BXE
Angle BXE = 2*72
Angle BXE = 144
Angle BXD = (angle BXE) - (angle DXE)
Angle BXD = 144 - 36
Angle BXD = 108
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Problem 26) 
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