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storchak [24]
3 years ago
10

Describe the method to make pure, dry crystals of magnesium sulfate from a metal oxide and dilute acid.

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

Explanation:

We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.

Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.

In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

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Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be su
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Volume = 746 L

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moles = \frac{Mass\ taken}{Molar\ mass}

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Moles= \frac{175\ g}{101.543\ g/mol}

Moles_{copper(II)\ fluoride}= 1.7234\ mol

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Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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Volume =\frac{Moles\ of\ solute}{Molarity}

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