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3 years ago

Describe the method to make pure, dry crystals of magnesium sulfate from a metal oxide and dilute acid.

Chemistry

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

Explanation:

We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.

Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.

In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

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Boil it. Kinetic energy is energy of motion and hot water moleculues move more

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3 years ago

Addition of 50. J to a 10.0-g sample of a metal will cause the temperature of a metal to rise from 25ºC to 35ºC. The specific he

Snowcat [4.5K]

Answer:

b) C = 0.50 J/(g°C)

Explanation:

Q = mCΔT

∴ Q = 50 J

∴ m = 10.0 g

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3 years ago

Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone

fenix001 [56]

Answer:

butyne

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3 years ago

Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.

bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr (1)

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = 181,66 kJ/mol

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = 0,216 kJ/Kmol

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ 4. +117,1 kJ/mol

I hope it helps!

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3 years ago

What are two qualities of metals? Describe each

Jlenok [28]

Answer:Typical physical properties of metals : high melting points. good conductors of electricity. good conductors of heat.

Explanation:

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1 year ago

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