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3 years ago

Describe the method to make pure, dry crystals of magnesium sulfate from a metal oxide and dilute acid.

Chemistry

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

Explanation:

We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.

Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.

In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

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2C3H7OH + 9O2 --> 6CO2 + 8H2O

Ne4ueva [31]

<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given] 5.55 mol C₃H₇OH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})$
Multiply/Divide: $\displaystyle 732.767 \ g \ CO_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

732.767 g CO₂ ≈ 733 g CO₂

8 0

3 years ago

How many moles are in a 111.5 gram sample of sodium chloride, NaCl?

Katarina [22]

Answer: 1.91 moles

Explanation:

First you want to find the molar mass of NaCL

Na = 22.99g Cl = 35.45g

22.99g + 35.45g = 54.44g

Then divide 111.5g by 54.44g and this will give you moles.

5 0

2 years ago

What is the volume, in liters, of 0.500 mol of c3h8 gas at stp? (hint..use avogadro’s principle to solve this)?

wolverine [178]

When we are at STP conditions, we can use this conversion: 1 mol= 22.4 L

0.500 mol C₃H₈ (22.4 L/ 1 mol)= 11.2 L

3 0

3 years ago

Read 2 more answers

For a trip to the Moon, a rocket must lift off from

VLD [36.1K]

Answer:

20 m/s^2

Explanation:

given,

final velocity (v) = 6000m/s

initial velocity (u) = 0m/s

time taken (t) = 5 minutes

= 5×60second

= 300second

acceleration(a) = ?

we know that,

a = (v-u)/t

= (6000-0)/300

= 20 m/s^2

5 0

3 years ago

How many molecules are there in 4.00 l of oxygen gas at 500.∘ c and 50.0 torr?

Oliga [24]

From the ideal gas law
pv=nRT , n is therefore PV/RT
R is the
R is gas constant =62.364 torr/mol/k
P=500torr
V=4.00l
T=500+273=773k
n={(500 torr x 4.00l)/(62.364 x773k)}=0.041moles
the number of molecules=moles x avorgadro costant that is 6.022x10^23)
6.022 x 10^23) x0.041=2.469 x10^22molecules

3 0

3 years ago