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kenny6666 [7]
3 years ago
15

Which statement describes the general trends in electronegativity and first ionization energy as the elements in Period 3 are co

nsidered in order from Na to Cl?
(1) Electronegativity increases, and first ionization energy decreases.

(2) Electronegativity decreases, and first ionization energy decreases.

(3) Electronegativity and first ionization energy both increase.

(4) Electronegativity and first ionization energy both decrease.
Chemistry
2 answers:
Andru [333]3 years ago
8 0
(3) Electronegativity and first ionization energy both increase describes the general trends in electronegativity and first ionization energy as the elements in Period 3 are considered in order from Na <span> to Cl.</span>
Alex17521 [72]3 years ago
4 0
Correct Answer: <span>(3) Electronegativity and first ionization energy both increase.

Reason:
Electronegativity and ionization energy are dependent on effective nuclear charge and size of atom.

As we move along the periodic table from left to right, atomic size decreases and effective nuclear charge increases. The increase in effective nuclear charge and decrease in atomic radii favor ionization energy and electronegativity. 

Hence, in 3rd period (from Na to Cl) electonegativity and 1st ionization energy increases. </span>
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calculate atomic weight of silver which has two isotopes with the following properties : silver-107 (106.91 amu, 51.84% natural
Julli [10]

Answer: The atomic weight of silver is 107.87 amu

Explanation:

Mass of isotope silver-107  = 106.91 amu

% abundance of isotope silver -107 = 51.84% = \frac{51.84}{100}=0.5184

Mass of isotope silver-109 = 108.90 amu

% abundance of isotope silver-109  = 48.16% = \frac{48.16}{100}=0.4816

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(106.91\times 0.5184)+(108.90\times 0.4816)]

A=107.87amu

Thus atomic weight of silver is 107.87 amu

8 0
4 years ago
Which type of cell is a rose thorn? prokaryotic eukaryotic plant eukaryotic animal chloroplastic
Ede4ka [16]
Plant cells<span> are </span>eukaryotic cells<span>. Prokaryotic </span>cells<span> do not contain a membrane bound nucleus, mitochondria or other membrane bound </span>cell<span> structures (organelles), the DNA of prokaryotic </span>cells<span> are located in the cytoplasm of the </span>cell<span>. ... </span>Plant cells<span> are </span>eukaryotic<span> because they have a nuclear membrane.
so therefore, A rose thorn is a eukaryotic plant cell.</span>
5 0
4 years ago
Read 2 more answers
How many orbitals surround the nucleus in a neutral atom of sulfur (S)? A. 1 B. 3 C. 9 D. 6
Igoryamba

Answer:

it may be 3

Explanation:

i hope that..

5 0
3 years ago
Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium
Anastaziya [24]

Answer:

Gd → Gd⁺ + 1e⁻, Gd⁺ → Gd⁺² + 1e⁻, Gd⁺² → Gd⁺³ + 1e⁻

Explanation:

The ionization energy is the energy necessary to remove one electron of the atom, transforming it in a cation. The first ionization energy is the energy necessary to remove the first electron, the second energy, to remove the second electron, and then successively.

Thus, for gadolinium (Gd)

Fisrt ionization:

Gd → Gd⁺ + 1e⁻

Second ionization:

Gd⁺ → Gd⁺² + 1e⁻

Third ionization:

Gd⁺² → Gd⁺³ + 1e⁻

3 0
4 years ago
first to answer correctly gets brainleist! (you dont needa hear that vid thingy tahts just for ppl who cant read or need orial c
Soloha48 [4]
I think the answer is c
7 0
3 years ago
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