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irinina [24]
4 years ago
13

Calculate the concentration of H3O+ in a solution that contains 5.5 × 10-5 M OH- at 25°C. Identify the solution as acidic, basic

, or neutral.
a. 1.8 × 10-10 M, acidic
b. 9.2 × 10-1 M, basic
c. 5.5 × 10-10 M, neutral
d. 9.2 × 10-1 M, acidic
e. 1.8 × 10-10 M, basic
Chemistry
1 answer:
defon4 years ago
6 0

Answer:

The correct answer is option (e).

Explanation:

Concentration of hydroxide ions [OH^-]= 5.5\times 10^{-5} M

The pOH of the solution is defined as negative logarithm of hydroxide ions of in an aqueous solution.

  • Higher the value of pOH more will be the acidic solution.
  • Lower the value of pOH more will be the basic solution.
  • At value  equal to 7 the solution is said to be neutral.

pOH=-\log[OH^-]

pOH=-\log[5.5\times 10^{-5} M]=4.259

pH +pOH = 14

pH = 14-pOH

pH=14 - 4.259 = 9.741

The pH of the solution is defined as negative logarithm of hydronium ions of in an aqueous solution.

  • Higher the value of pH more will be the basic solution.
  • Lower the value of pH more will be the acidic solution.
  • At value equal to 7 the solution is said to be neutral.

pH=-\log[H_3O^+]

9.741=-\log[H_3O^+]

[H_3O^+]=1.8\times 10^{-10} M

The solution is basic as pH of the solution is 9.741.

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3 years ago
A solution has a pH of 4.20. Using the relationship between pH and pOH, what is the concentration of OH?? A. 9.9 × 10-1 M B. 6.2
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The correct answer is option E.

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ions  concentration in a solution. Mathematically written as:

pH=-\log[H^+]

The pOH of the solution is defined as negative logarithm of hydroxide ions  concentration in a solution. Mathematically written as:

pOH=-\log[OH^-]

The sum of ph and pOH is equal to 14.

pH + pOH = 14

A solution has a pH of 4.20.

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pOH=9.8=-\log[OH^-]

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Hence, the correct answer is option E.

5 0
3 years ago
How much heat (in kj) is evolved in converting 1.00 mol of steam at 130.0 ∘c to ice at -55.0 ∘c? the heat capacity of steam is 2
nevsk [136]

The heat will be evolved in following process:

1) cooling steam from 130^{0}C to 100^{0}C = Q1

2) conversion of steam to water =Q2

3) Cooling of water to 0^{0}C[/tex=Q3]4) conversion of water to ice=Q45) cooling of ice from [tex]0^{0}C to -55^{0}C=Q5

Let us calculate each energy one by one:

1) Q1:

Mass of water vapour = moles X molar mass = 1mol X 18 = 18 grams

heat capacity of steam is 2.01\frac{J}{g^{0}C }

Q_{1}=massXheat capacityXchangeintemperature=18X2.01X(130-100)=-1085.4J

2) Q2:

for this we need heat of vaporisation of water = -40.7kJ/mol

so the heat evolved in conversion of stem to water is -40.7kJ

3) Q3

the specific heat of water is 4.18\frac{J}{g^{0}C }

heat evolved in cooling of water will be Q_{3}=massXspecific.heatXchange.in.temperature=18X4.184X100=7531.2J=7.531kJ

4)Q4:

The heat of conversion of ice to water (melting) is 6.02kJ/mol

5) Q5

The cooling of ice will require

Q_{5}=massXspecificheatXchangeintemperature=18X2.09X(-55)=-2069.1J=-2.069kJ

The total energy released is

Q_{total}=Q1+Q2+Q3+Q4+Q5=1.085+40.7+7.531+6.02+2.069=59.474kJ

The heat released will be 59.474 kJ


5 0
3 years ago
Determine the type of reaction: H2O + C16H17NaO14 = CO2 + H20 + C2H3NaO3?
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Answer:

It is the type of Decomposition reaction.

Explanation:

<em>A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. These reactions often involve an energy source such as heat, light, or electricity that breaks apart the bonds of compounds.</em>

In this reaction , C16H17NaO14 decomposes to give carbon dioxide and C2H3NaO3.

That's why , this reaction is a decomosition reaction.

6 0
3 years ago
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