What are the conditions of an EF4?

Why is using only clean glassware important?

stealth61 [152]

Good laboratory technique demands clean glassware because the most carefully executed piece of work may give an erroneous result if dirty glassware is used. In all instances, glassware must be physically and chemically clean and in many cases, it must be bacteriologic-ally clean or sterile.

6 0

3 years ago

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20. Which of the following elements would you expect to lose one electron? Select all that apply.

Jobisdone [24]

Answer:

Sodium and Potassium only

5 0

2 years ago

(a) what is the approximate ductility (%el) of a brass that has a yield strength of 230 mpa (33360 psi)?

ss7ja [257]

Based on the calculations, the approximate ductility (%el) of this brass is equal to 2.3%.

<u>Given the following data:</u>

Yield strength = 230 mpa (33360 psi).

<h3>What is ductility?</h3>

Ductility can be defined as an important property of a material which determines its ability to become elongated due to the application of stress.

Mathematically, the ductility of a material can be expressed as percentage elongation in length:

$\% el = \frac{\Delta L}{L_i} =\frac{L_f - L_i}{L_i}$

<u>Where:</u>

$L_i$ is the original length.

$L_f$ is the final length.

$\Delta L$ is the yield strength.

For this exercise, let us assume the original length of this brass is equal to 100 meters.

Substituting the parameters into the formula, we have;

$\% el = \frac{230}{100}$

Ductility = 2.3%.

Read more on ductility here: brainly.com/question/828860

3 0

2 years ago

Noble gas compounds like KrF, XeCl, and XeBr are used in excimer lasers. Draw an approximate molecular orbital diagram appropria

Aneli [31]

Answer:

Here's what I get.

Explanation:

The MO diagrams of KrBr, XeCl, and XeBr are shown below.

They are similar, except for the numbering of the valence shell orbitals.

Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.

However, the MO diagrams are approximately correct.

The ground state electron configuration of KrF is

$(1\sigma_{g})^{2}\, (1\sigma_{u}^{*})^{2} \, (2\sigma_{g})^{2} \, (2\sigma_{u}^{*})^{2} \, (3\sigma_{g})^{2} \, (1\pi_{u})^{4} \, (1\pi_{g}^{*})^{4} \, (3\sigma_{g}^{*})^{1}$