let's first off convert those mixed fractions to improper fractions, then get their difference.
![\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}~\hfill \stackrel{mixed}{2\frac{1}{10}}\implies \cfrac{2\cdot 10+1}{10}\implies \stackrel{improper}{\cfrac{21}{10}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{21}{10}-\cfrac{3}{2}\implies \stackrel{\textit{using the LCD of 10}}{\cfrac{(1)21-(5)3}{10}}\implies \cfrac{21-15}{10}\implies \cfrac{6}{10}\implies \cfrac{3}{5}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B3%7D%7B2%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%2010%2B1%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B21%7D%7B10%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B21%7D%7B10%7D-%5Ccfrac%7B3%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%2010%7D%7D%7B%5Ccfrac%7B%281%2921-%285%293%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B21-15%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B6%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B5%7D)
now, the original amount, 3/2, if that is the 100%, what is 3/5 off of it in percentage?

The new line will have the same slope as the old one.
y = x + 4
y = x + b is the new line
We solve for b by using (2,2)
When x = 2
y = 2
2 = 2 + b
b = 0
Therefore the new line is
y = x
0.1846 as a fraction=1846\10000
Answer:
Area is the measure of the amount of surface covered by something. Area formulas for different shapes are sometimes different, but for the most part, area is calculated by multiplying length times width. This is used when calculating area of squares and rectangles. Once you have the number answer to the problem, you need to figure out the units. When calculating area, you will take the units given in the problem (feet, yards, etc) and square them, so your unit measure would be in square feet (ft.2) (or whatever measure they gave you).
Step-by-step explanation:
Answer:
Distance from the airport = 894.43 km
Step-by-step explanation:
Displacement and Velocity
The velocity of an object assumed as constant in time can be computed as

Where
is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as


The displacement of the plane in 2 hours is


Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are


The displacement in 1 hour is


The total displacement is the vector sum of both



The distance from the airport is the module of the displacement:

