First find the slope of f(x).
m=(y2-y1)/(x2-x1)
m=(1-5)/(2-0)
m=-4/2
m=-2
y=-2x+b, using (2,1) we can solve for the y-intercept, "b"
1=-2(2)+b
1=-4+b
5=b
y=-2x+5
So f(x) has a y-intercept of 5
g(x)=6m+3
So g(x) has a y-intercept of 3
h(x)=3x+4
So h(x) has a y-intercept of 4
Then g(x) has the lowest y-intercept of just 3.
Answer:
it's just 8/20 so shade 8/20 of the circle
Answer:
30 degrees
Step-by-step explanation:
u dot v=1*4+1*4+1*4+0*4=4+4+4+0=12
|u|=sqrt(1^2+1^2+1^2+0^2)=sqrt(3)
|v|=sqrt(4^2+4^2+4^2+4^2)=sqrt(4*4^2)=2*4=8
cos(theta)=u dot v/(|u||v|)
cos(theta)=12/(sqrt(3)*8)
cos(theta)=3/(sqrt(3)*2)
cos(theta)=sqrt(3)/2
theta=30 degrees
The expressions that can represent the dimensions of the prim is (x), (3x+1) and (4x-1).
