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2 years ago

Find the midpoint of (-3,7) and (-9,1).

Mathematics

2 answers:

STatiana [176]2 years ago

5 0

(-6,4) is your mid point

Temka [501]2 years ago

3 0

Answer:

(-6, 4)

Step-by-step explanation:

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Answer all three questions please

jeka57 [31]

Answer:

A iS THE ANSWER

Step-by-step explanation:

6 0

2 years ago

An 8-pound boneless ham contains 36 servings of meat. What is the ratio in servings per pound?

juin [17]

Answer:

9 servings of meat.

Step-by-step explanation:

The first ratio you are given is 8:36. You are trying to figure out what 2:__ is.

8/36 x 2/X

Multiply 2 x 36 and get 72. Now divide 72 by 8 to get 9.

7 0

2 years ago

A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su

Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let $\mu_1$ = mean sales per market in Region 1.

$\mu_2$ = mean sales per market in Region 2.

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, $H_A$ : > $\mu_1-\mu_2\neq$ 0 {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean sales in Region 1 = 84

$\bar X_2$ = sample mean sales in Region 2 = 78.3

$s_1$ = sample standard deviation of sales in Region 1 = 6.6

$s_2$ = sample standard deviation of sales in Region 2 = 8.5

$n_1$ = sample of supermarkets from Region 1 = 12

$n_2$ = sample of supermarkets from Region 2 = 17

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times 8.5^{2} }{12+17-2} }$ = 7.782

So, the test statistics = $\frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }$ ~ $t_2_7$

= 1.943

The value of t-test statistics is 1.943.

Now, at a 0.02 level of significance, the t table gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0

3 years ago

How far is 75% of a 2,000-kilometer trip

zubka84 [21]

Answer: 1500 kilometers

75% of a 2000 - kilometer trip is 1500 kilometers

Step-by-step explanation:

6 0

2 years ago

As baby boomers enter their golden years, the number of people afflicted with Alzheimer's disease is expected to rise dramatical

dybincka [34]

Answer:

Step-by-step explanation:

Given that the number of people with Alzheimer's disease in the United States age 65 years and over is projected to be

$N(t) = 0.00525t^2 +0.075t+4.7,(0 ≤ t ≤ 4)$

where N is in millions where year 2010 corresponds to t=0

For 2020, 10 years lapsed hence t= 1

a) $N(1) = 0.00525(1)^2 + 0.075(1) + 4.7\\=4.78025$

So 4.78025 million people

b) Growth = N(1)-n(0) =0.08025 million

c) N(4) = 5.084

Average rate of change = (5.084-4.7)/4 =0.096 million per decade

4 0

3 years ago

Find the midpoint of (-3,7) and (-9,1).​

Find the midpoint of (-3,7) and (-9,1).