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3 years ago

Need help with my geometry test. Got no idea how to do it.

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

7 0

Answer:

Should be D: Area multiplied by 1/3

Step-by-step explanation:

So since your radius is being multiplied by 1/3, so is your area. I think.

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I attached da picture

Svetach [21]

1. withdrawals would be negative, deposits would be positive
2. -102.47
3. yes, because he spent $40 in addition to his -$62.47 balance. this would make his balance come to -$2.47

7 0

2 years ago

Yves bought 420 tropical fish for a museum display. He bought 6 times as many parrotfish as angelfish. How many of each type of

ohaa [14]

The answer would be d , because you have to add how many of each fish to equal up to the sum of 420 . which is x y . so the first equation is x + y = 420 . then it says he bought 6 times as many parrotfish as he did angelfish so you would have to multiply x which represents angelfish by 6 . to get the second equation of y = 6x .

5 0

2 years ago

Read 2 more answers

Dominic and Tyler collected soda cans to raise money. Dominic collected 700 cans and Tyler collected 7000 cans. The number of ca

Crank

It should be ten times greater since,

700x10=7000

So ten times greater.

4 0

3 years ago

This is a question on my partial fractions homework, but no matter what I try I can't figure it out..

Ierofanga [76]

$\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}$
$\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}$
$\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)$
$\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3$

So you have

$\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$
$=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$

where in the first integral we substitute $x\mapsto x+1$ .

$=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}$
$=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)$
$=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2$
$=\dfrac23+\ln\dfrac89$

4 0

3 years ago

A square field has an area of 144 metres squared. If Andrea walked 10 times around this field, what distance did she cover?

Novosadov [1.4K]

Answer:

480m

Step-by-step explanation:

First we have to find the perimeter of the field.

We know that the area is 144m and that the field is a square.

Since a squares sides are all equal, we can do $\sqrt{144}$ , which is 12m.

So, one side of the field is 12m; now we just find the perimeter which is easy since its a square. 12*4=48m

If Andrea walked around it 10 times, then we just multiply the perimeter by 10

48*10=480m

7 0

2 years ago