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3 years ago

14) When did the high temperature occur? Please help

Mathematics

2 answers:

timama [110]3 years ago

5 0

Answer:

D; 15

Step-by-step explanation:

Because the highest point on the graph is at 15 (or 3 am), that would be the highest temperature. (Also, none of the other choices make sense; they are all at relatively low temperatures).

Sonja [21]3 years ago

4 0

The answer to ur question is d.15

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C = .25t +3.50 in 'C' dollars for 't' minutes. How much does it cost to rent the canoe for 1 hour?

yKpoI14uk [10]

Answer and Step-by-step explanation:

We know that t is in minutes, and 1 hours is equal to 60 minutes, so we plug in 60 for t.

C = 0.25(60) + 3.50

C = 15 + 3.50

C = 18.50

The cost to rent the canoe is $18.50.

#teamtrees #PAW (Plant And Water)

8 0

3 years ago

Read 2 more answers

The sum of three numbers is 95. The first number is 5 more than the third. The second number is 4 times the third. What are the

kotykmax [81]

Answer:

20, 60, 15

Step-by-step explanation:

Let the third number be n, then

The first number is n + 5 and the second number is 4n

Sum the 3 numbers and equate to 95, that is

n + 5 + 4n + n = 95 ← collect like terms on left side

6n + 5 = 95 ( subtract 5 from both sides )

6n = 90 ( divide both sides by 6 )

n = 15

Thus

The first number is 15 + 5 = 20

The second number is 4 × 15 = 60

The third number is 15

4 0

4 years ago

Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

7 0

3 years ago

Need help with homework

motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation: