All categories

2 years ago

Helppppppp meee ASAP

Mathematics

2 answers:

balandron [24]2 years ago

6 0

$75|5\\15|5\\.\ 3|3\\.\ 1|\\75=\boxed{5}\cdot\boxed{5}\cdot3\\\\100|5\\.\ 20|5\\.\ \ 4|2\\.\ \ 2|2\\.\ \ 1|\\100=\boxed{5}\cdot\boxed{5}\cdot2\cdot2\\\\175|5\\.\ 35|5\\.\ \ 7|7\\.\ \ 1|\\175=\boxed{5}\cdot\boxed{5}\cdot7\\\\GCF(75;\ 100;\ 175)=\boxed{5}\cdot\boxed{5}=25$

Answer: 25

pentagon [3]2 years ago

6 0

Answer is C, 25. 75 doesn't go into 100 or 175 evenly, so that wouldn't work, 20 only goes into 100 evenly, and 5 goes into all of them, but it's not the greatest common factor. 25 works for all 3, and it is the greatest number that works, so it is the greatest common factor, or GCF. So it has to be C, 25.

You might be interested in

6. Write the equation of the line in slope-intercept form that has the following points: (1, -3) (0, -5)

Troyanec [42]

Answer:

y = 2x −5

Step-by-step explanation:

The slope is 2 and the Y intercept is -5 so the equation is:

y = 2x -5

7 0

1 year ago

How do u factor this

PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

$p(x)=x^2+bx+c$

has roots $x_1,\ x_2$ , then you have the following factorization:

$p(x) = (x-x_1)(x-x_2)$

In order to find the roots, you can use the usual formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the first example, this formula leads to

$x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}$

So, you can factor

$x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})$

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

$f(1.5)=-5.25$

you get

$f(-1.5) = 1.5c-3 = -5.25$

Add 3 to both sides:

$1.5c = -2.25$

Divide both sides by 1.5:

$c = 1.5$

7 0

3 years ago

A + 3(a - 1)= 3(2 +1)

N76 [4]

A+3a-3=6+3. 4a=12. a=3.

5 0

2 years ago

Rectangle with an area of 16 with a perimeter of 20

Assoli18 [71]

An 8 by 2 rectangle
have a nice day!

4 0

2 years ago

How to expand 3(2t+1)

Vlada [557]

Hey there :)

3 ( 2t + 1 )
We use what is called the distributive property to get rid of the parenthesis

We multiply the term outside the parenthesis by all terms inside
3 ( 2t ) + 3 ( 1 )

6t + 3 → Your answer

8 0

3 years ago