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Dmitrij [34]
3 years ago
5

What are the x values of a relation

Mathematics
2 answers:
lara [203]3 years ago
8 0

Answer:

x values are the independent values

kotegsom [21]3 years ago
6 0

The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values).
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marta [7]
10 x 5 = 50
4 x 7 = 28
3 x 4 = 12 12/2=6

50+28+6= 84 square inches
6 0
3 years ago
Bryan has 24 toy cars Jason has 12 toy cars what is the ratio
Rudik [331]
The ration is 2:1  bryan has twice as many as jason
6 0
3 years ago
Pleaseee help me asap
pychu [463]

Answer:

k = 13.5

Step-by-step explanation:

Setup proportion and solve for k:

\frac{k}{9} =\frac{4.5}{3} \\3k = 40.5\\k=13.5

8 0
3 years ago
4. Assume that the chances of a basketball player hitting a 3-pointer shot is 0.4 and the probability of hitting a free-throw is
vovikov84 [41]

Answer:

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of making 3 3-pointers out of 10:

The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that p = 0.4. So this is P(X = 3) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.21499

Probability of making 5 free throws out of 10:

The probability of hitting a free-throw is 0.65, which means that p = 0.65. The probability is P(X = 5) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{10,5}.(0.65)^{5}.(0.35)^{5} = 0.15357

Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

5 0
3 years ago
brianna's house is at (1,6). jordan's house is at (5,3). what is one possible path from brainna's house to jordan's house?
Fittoniya [83]
(3,1.67) could be a possible path
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3 years ago
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