A car rental company charges $0.10 per mile plus an initial fee of $120 for the rental of a midsize sedan. If Lawrence rents a v
ehicle and has $200, what is the maximum number of miles he can drive
1 answer:
Answer:
800 miles
Step-by-step explanation:
Set up an equation, where x is the number of miles driven:
0.10x + 120 = 200
Then, solve for x:
0.10x = 80
x = 800
So, the maximum number of miles he can drive is 800 miles
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Answer:
on the 5th week they would both have the same amount of money they would both have a total of 85$
Step-by-step explanation:
So let's start from the beginning.
Add 2 and 4:
(2 + 4)
Multiply the sum by 3:
3(2 + 4)
Then add 5 to that product:
3(2 + 4) + 5
Then double the results:
2[3(2 + 4) + 5]
OK 33*76= 2508 if that is your question if its not tell me and i will see what i can do
16000x9%x5 is $7200 #1 is $7200
16000x9%x3 is $2400 soo 7200-2400 is 4800 sooo
#1 is $7200
#2 is he or she will save $4800
now solve the quadretic eq. for the value of a
I hope it help to u
