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jeyben [28]
3 years ago
10

A car rental company charges $0.10 per mile plus an initial fee of $120 for the rental of a midsize sedan. If Lawrence rents a v

ehicle and has $200, what is the maximum number of miles he can drive
Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

800 miles

Step-by-step explanation:

Set up an equation, where x is the number of miles driven:

0.10x + 120 = 200

Then, solve for x:

0.10x = 80

x = 800

So, the maximum number of miles he can drive is 800 miles

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Sonja [21]
The answer to the question

6 0
3 years ago
Help me PLEASE!!!!!<br><br> 3x = 27<br><br> x = ? <br><br> Thank you!!
steposvetlana [31]
We will use the INVERSE OPERATION of multiplication which is division. Lets do it:-

3x = 27
27 ÷ 3 = x
27 ÷ 3 = 9
x = 9

CHECK OUR WORK:-

3x = 27
x = 9
3 · 9 = 27
We were RIGHT!!!!!

So, x = 27.

Hope I helped ya!!! xD
6 0
3 years ago
Read 2 more answers
5(8n+ 7) &lt; 5-5(n+3)
svet-max [94.6K]

Answer:

n<-1

Step-by-step explanation:

Distribute 5 and -5 into each parenthesis respectively: 40n+35<5-5n-15

Combine like terms: 40n+35<-5n-10

Add 5n to both sides: 45n+35<-10

Subtract 35 from both sides: 45n<-45

Divide both sides by 45: n<-1

3 0
3 years ago
NEED HELP ASAP, PLEASE
kozerog [31]

Answer:

3

Step-by-step explanation:

8x and 7x + 3 are vertically opposite angles.

Vertically opposite angles are equal,

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8x - 7x = 3

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6 0
2 years ago
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What are the real and complex solutions of the polynomial equation X^3-216=0
vazorg [7]

Answer:

6,\ -3+3\sqrt{3}i,\ -3-3\sqrt{3}i

Step-by-step explanation:

Factor the equation x^3-216=0 using formula for difference of the cubes:

x^3-216=(x-6)(x^2+6x+36),

then

x-6=0\ or\ x^2+6x+36=0.

1. The equation x-6=0 has real solution x=6.

2. The equation x^2+6x+36=0 has negative discriminant D=6^2-4\cdot 36=36-144=-108, then it has two complex solutions

x_{1,2}=\dfrac{-6\pm 6\sqrt{3}i}{2}=-3\pm3\sqrt{3}i.

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3 years ago
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