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lord [1]
3 years ago
5

In ΔABC, the measure of ∠C=90°, AC = 40, BA = 41, and CB = 9. What is the value of the tangent of ∠B to the nearest hundredth? *

WILL MARK BRAINLIEST*
Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

4.44

Step-by-step explanation:

The tangent of B is the relation of the opposite cathetus to the lying cathetus

tg B= AC/CB= 40/9= 4.44

You might be interested in
5 2/3 divided by 3/2
Zinaida [17]

Answer: 34/9

Step-by-step explanation:

5  2/3  /   3/2

= 17/3  /   3/2

=17/3 x 2/3        [reciprocal]

=34/9

Hope it helped u,

pls mark as the brainliest

^_^

7 0
3 years ago
Read 2 more answers
6) The amount of Jen's monthly phone bill is normally distributed with a mean of $70 and a standard
alexandr402 [8]

Answer:

i)The correct option is  D.) 99.74%

ii) The correct option is B.) 68.26%

Step-by-step explanation:

i) P(10≤X≤70) = P(  (10−40)/10  ≤Z≤   (70−40 )/10 ) =  Pr(−3≤Z≤3)

= 0.9987 - 0.0013 = 0.99734

Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%

ii)P(2.1≤X≤3.1) = P(  (2.1 − 2.6) /0.5   ≤ Z  ≤ (3.1−2.6 )/0.5)  =  Pr(−1  ≤Z  ≤1) )

=  0.8413 − 0.1587  =  0.6826

Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%

5 0
3 years ago
Subtract 6 1/3 - 4 1/9​
Debora [2.8K]

Answer:

2 2/9

Step-by-step explanation:

6 0
3 years ago
In this equation, y-4/2=10, would i need to get the same denominator<br> y-4/2=10/2 = y-2=5?
Natasha_Volkova [10]
No actually you can just multiply both sides of the equation by 2 and get y-4=20. then add 4 to both sides to get y=24.
3 0
3 years ago
A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter
Andre45 [30]

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

x+y=15\operatorname{cm}

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}

We can now refine the equation as follow;

\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}

ANSWER:

The length of the shorter piece of wire is 6cm

7 0
1 year ago
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