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Vedmedyk [2.9K]
3 years ago
13

Multiplying a number by 2 and then dividing by 3 is the same as multiplying by what a number

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0
Multiplying a number by 2 and then dividing by 3 is the same as multiplying by \frac{2}{3}, or, 0.666...
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Find the length of the hypothenuse of the right triangle with legs that measure 5 and 7. Brianlest for anyone who can give step
zepelin [54]
To calculate hypothenuse you use the formula a^2+b^2=c^2 where c is the length of the hypothenuse.

1. 5^2+7^2=c^2
2.25+49=74
3. Now you will square root the 74
4. The hypothenuse is equal to 8.6
4 0
4 years ago
Write an algebraic expression that models each word phrase four more than a number b
Alisiya [41]
The answer would be the first choice 4+b
5 0
3 years ago
Write the equation of a line perpendicular to 2x + 3y = 4 and passing through (-3,-5).
Tasya [4]

Answer:

Step-by-step explanation:

A line perpendicular to the given line has a slope that is the negative inverse of the reference line.  

Rewrite the given equation in the format of y=mx+b, where mi is the slope and b is the y-intercept (the value of y when x = 0.

2x + 3y = 4

3y=-2x+4

y = -(2/3)X + (4/3)

The reference slope is -(2/3).  The negative inverse is (3/2), which will be the slope of a perpendicular line.  We can write the new line as:

y = (3/2)x + b

Any value of b will still result in a line that is perpendicular.  But we want a value of b that will shift the line so that it intersects the point (-3,-5).  Simply enter this point in the above equation and solve for b.

y = (3/2)x + b

-5 = (3/2)(-3) + b

-5 = -(9/2) + b

-5 = -4.5 + b

b = - 0.5

The equation of the line that is perpendicular to 2x + 3y = 4 and includes point (-3,-5) is

y = (3/2)x - 0.5

6 0
2 years ago
An ellipse has a center at the origin, a vertex along the major axis at (0, 17), and a focus at (0, −8). Which equation represen
Marianna [84]
We know that
<span>Since the focus and vertex are above and below each other, rather than side by side, I know that this ellipse must be taller than it is wide.
</span>Then 
a²<span> will go with the </span>y<span> part of the equation
</span>Also, since the focus is 8 <span>units below the center, then </span><span>c = 8
</span>since the vertex is 17<span> units above, then </span><span>a = 17
</span>The equation b²<span> = a</span>²<span> – c</span>²<span> gives me
</span>b²=17²-8²-----> b²=225
the equation is
y²/a²+x²/b²=1------> y²/289+x²/225=1

the answer is
y²/289+x²/225=1

see the attached figure

7 0
4 years ago
Read 2 more answers
What is the horizontal asymptote of j(x) =
Korvikt [17]

Answer: y=7

Step-by-step explanation:

8 0
3 years ago
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