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jekas [21]
1 year ago
6

A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter

piece of wirecm
Mathematics
1 answer:
Andre45 [30]1 year ago
7 0

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

x+y=15\operatorname{cm}

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}

We can now refine the equation as follow;

\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}

ANSWER:

The length of the shorter piece of wire is 6cm

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<h3>What is the monthly payment formula?</h3>

It is given by:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

In which:

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In this problem, we have that the parameters are given as follows:

A = 400, n = 70, r = 0.035.

Hence:

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Then we have to solve for P to find the maximum value of the car.

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 P(X = 8) =  0.0037

b

 P(X <  5) =  0.805

c

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I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is p = 0.267

Generally data collected from this study follows  binomial  distribution because the number of trials is  finite , there are only two outcomes, (covering  , and  not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable  X we have that  

   X \ \ \~ \ \ { B ( p , n )}

The probability distribution function for binomial  distribution is  

    P(X = x ) =  ^nC_x *  p^x *  (1 -p) ^{n-x}

Considering question a

Generally the  the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when​ sneezing is mathematically represented as

     P(X = 8) =  ^{12} C_8 *  (0.267)^8 *  (1- 0.267)^{12-8}

Here C denotes  combination

So

     P(X = 8) =  495  *  0.000025828 * 0.28867947

    P(X = 8) =  0.0037

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when​ sneezing is mathematically represented as

     P(X <  5 ) =[P(X = 0 ) + \cdots + P(X = 4)]

=>   P(X <  5 ) =[ ^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0} + \cdots +  ^{12} C_4 *  (0.267)^4 *  (1- 0.267)^{12-4} ]

=> P(X <  5 )  =  0.02406 +  0.10516 + 0.21067 + 0.25580 + 0.20964

=>  P(X <  5) =  0.805

Considering question c

Generally the probability that fewer than half(6) covered their mouth when​ sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

      P(X > 6) =  1 - p(X \le  6)

=>    P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)]

=>    P(X > 6)=1 - [^{12} C_0 *  (0.267)^0 *  (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 *  (0.267)^6 *  (1- 0.267)^{12-6} ]

=>    P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ]  

=>    P(X > 6) =  0.0206

I would be surprised because the value is very small , less the 0.05

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