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2 years ago

Find an equation of the tangent line to the curve at the given point. y = ln(x2 ? 7x + 1), (7, 0)

1 answer:

3 0

Take derivitive
remember chain rule
dy/dx=1/(x² ? 7x+1) times (2x ? 7)
dy/dx=(2x ? 7)/(x² ? 7x+1)
inputting x=7

the slope at x=7 is (14 ? 7)/(49 ? 49+1)=(14 ? 7)/(49 ? 50)
the slope is (14 ? 7)/(49 ? 50)
use point slope form
y-0=(14 ? 7)/(49 ? 50)(x-7)
y=(14 ? 7)/(49 ? 50)(x-7)

I'm going to take a wild guess that the ? means minus because you were able to type a plus sign
in that case, it would be
y=-2(x-7)

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The distribution of the amount of money in savings accounts for Florida State students has an average of 1,200 dollars and a sta

Anestetic [448]

Answer:

By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average of 1,200 dollars and a standard deviation of 900 dollars.

This means that $\mu = 1200, \sigma = 900$

Sample of 10.

This means that $n = 10, s = \frac{900}{\sqrt{10}} = 284.6$

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

7 0

2 years ago

6. Mike's family went to the YES Prep Volleyball game. Mike bought 1 ticket, 2 chips and a drink

KIM [24]

Answer:

x=5

y=1

z=2

Step-by-step explanation:

x+2y+z=9

3x+y+4z=24

x+3y+z=10

6 0

3 years ago

Help please jggvnhujff

saveliy_v [14]

Answer:

Step-by-step explanation:

8). $\left \{ {{4x+3y=1} \atop {x+y=2}} \right.$

(2) × [ - 3 ]

4x + 3y = 1 ........ (3)

- 3x - 3y = - 6 .... (4)

(3) + (4)

x = - 5

- 5 + y = 2 ⇒ y = 7

( - 5 , 7 )

9). $\left \{ {{-9x+3y=18} \atop {2x+y=-4}} \right.$

(1) ÷ [- 3]

3x - y = - 6 ......... (3)

2x + y = - 4 ........ (4)

(3) + (4)

5x = - 10 ⇒ x = - 2

2(- 2) + y = - 4 ⇒ y = 0

(- 2, 0)

10). $\left \{ {{x-2y=14} \atop {10x-6y=0}} \right.$

(2) ÷ 10

x - 0.6y = 0 ⇒ x = 0.6y -----> (1)

0.6y - 2y = 14

- 1.4y = 14

y = - 10

x - 2(- 10) = 14 ⇒ x = - 6

(- 6, - 10)

Now is your turn, you can do it!!

3 0

2 years ago

What are the x-intercepts of the graph of the quadratic function

Svetllana [295]

Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.

(Make sure to set f(x) to zero)

So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: $0=5x^2+5x-x-1$

Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: $0=5x(x+1)-1(x+1)$

Now you can rewrite the equation as: $0=(5x-1)(x+1)$

Now apply zero product property to the factors to solve for x:

$5x-1=0\\5x=1\\x=\frac{1}{5}\\\\x+1=0\\x=-1$

The x-intercepts are (1/5 ,0) and (-1,0).

5 0

3 years ago

A tank is filled at a constant rate. 10 minutes after filling is started, the tank contains 4.8L of water. After 35 minutes the

Mashcka [7]

Answer:

Part A)

0.1 liters per minute.

Part B)

There was initially 3.8 liters of water.

$\displaystyle V(t) = 0.1(t - 10) + 4.8$

Part C)

562 minutes.

Step-by-step explanation:

A tank is filled at a constant rate. After 10 minutes, the tank contains 4.8 L of water and after 35 minutes, the tank contains 7.3 L of water.

Part A)

We can represent the current data with two points: (10, 4.8) and (35, 7.3). The x-coordinate is measured in minutes since the tank began to be filled and the y-coordinate is measured in how full the tank is in liters.

To find the rate at which the tank is being filled, find the slope between the two points:

$\displaystyle m = \frac{\Delta y}{\Delta x} = \frac{(7.3)-(4.8)}{(35)-(10)} = \frac{2.5}{25} = 0.1$

In other words, the rate at which the tank is being filled is 0.1 liters per minute.

Part B)

To find the function of the volume of the tank, we can use the point-slope form to first find its equation:

$\displaystyle y - y_1 = m( x - x_1)$

Where m is the slope/rate of change and (x₁, y₁) is a point.

We will substitute 0.1 for m and let (10, 4.8) be the point. Hence:

$\displaystyle y - (4.8) = 0.1(x - 10)$

Simplify:

$\displaystyle y = 0.1(x-10) + 4.8$

Since y represent how full the tank is and x represent the time in minutes since the tank began to be filled, we can substitute y for V(t) and x for t. Thus, our function is:

$\displaystyle V(t) = 0.1(t - 10) + 4.8$

The initial volume is when t = 0. Evaluate:

$\displaystyle V(0) = 0.1 ((0) - 10) + 4.8 = 3.8$

There was initially 3.8 liters of water.

Part C)

To find how long it will take for the tank to be completely filled given its maximum capacity of 60 liters, we can let V(t) = 60 and solve for t. Hence:

$60 = 0.1(t - 10) + 4.8$

Subtract:

$55.2 = 0.1(t - 10)$

Divide:

$552 = t - 10$

Add. Therefore:

$t = 562\text{ minutes}$

It will take 562 minutes for the tank to be completely filled.

8 0

2 years ago