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Fantom [35]
3 years ago
13

Does anybody know this? 21 + 3 + (8 -2 +2)

Mathematics
1 answer:
Maurinko [17]3 years ago
8 0
By law of BIDMAS, we must start with brackets
= (8-2+2)= 8
21 + 3= 24
24 + 8 = 32
Hope this helps, have a nice day!:)
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Ford and GM pick up trucks are being tested for fuel efficiency, which is commonly measured in miles per gallon (mpg). The fuel
lina2011 [118]

Answer:

0.7881 = 78.81% probability that a randomly chosen Ford truck outperforms a randomly chosen GM truck in terms of fuel efficiency

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, and the standard deviation is the square root of the sum of the variances.

The fuel efficiency of Ford trucks is found to follow a normal distribution with mean 20 mpg and a standard deviation of 3 mpg.

This means that \mu_{F} = 20, \sigma_{F} = 3

The fuel efficiency of GM trucks is found to follow a normal distribution with mean 24 mpg and standard deviation of 4 mpg.

This means that \mu_{G} = 24, \sigma_{G} = 4

Compute the probability that a randomly chosen Ford truck outperforms a randomly chosen GM truck in terms of fuel efficiency

This is the probability that the subtraction of ford by gm is less than 0. First, we find the mean and the standard deviation.

\mu = \mu_{F} - \mu_{G} = 20 - 24 = -4

\sigma = \sqrt{\sigma_{F}^2+\sigma_{G}^2} = \sqrt{3^2+4^2} = 5

This probability is the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - (-4)}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881

0.7881 = 78.81% probability that a randomly chosen Ford truck outperforms a randomly chosen GM truck in terms of fuel efficiency

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Answer:

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Step-by-step explanation:

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ruslelena [56]

Answer:

y=4x+47

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3 years ago
Read 2 more answers
Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

3a^{4} + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

<u>Now we can evaluate the terms in the brackets. </u>

(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)

<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18

<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

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The answer is 49806.06. 
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