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just olya [345]

2 years ago

6

Hey guys do any of you guys know the answer to this? I’m struggling with it and I still don’t know the answer plz help me! Thank

s!

1 answer:

Sunny_sXe [5.5K]2 years ago

4 0

Answer:

steps below

Step-by-step explanation:

DE/WX = 15/35 = 3/7

DF/WY = 24/56 = 3/7

EF/XY = 18/42 = 3/7

ΔDEF similar to ΔWXY (sss) : 3 corresponding sides are in the same ratio

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Find the slope of the line that passes through (1, 8) and (10, 1).

leonid [27]

Answer:

$m = \frac{1 - 8}{10 - 1} = - \frac{ 7}{9} \\$

Slope(gradient)=

$-\frac{7}{9}$

Good luck!

Intelligent Muslim,

From Uzbekistan.

8 0

3 years ago

Read 2 more answers

Mrrafil [7]

Answer:

3280

Step-by-step explanation:

52×63=3276

Round 3276 to 3280

Hope this helps! :)

3 0

2 years ago

A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)

Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}$

5 0

3 years ago

Identify the center and the radius of each.<br><br> x^+y^+26x-22y+281=0

inessss [21]

Answer:

Center (-13,11) , radius 3

Step-by-step explanation:

The given circle has equation

$x^2+y^2+26x-22y+281=0$

We compare this to the general equation.

$x^2+y^2+2ax+2by+c=0$

where (-a,-b) is the center.

This implies that;

2a=26

$\Rightarrow a=13$

2b=-22

b=-11

The center is therefore (-13,11)

The radius is given by

$r=\sqrt{a^2+b^2-c}$

$r=\sqrt{13^2+(-11)^2-281}$

$r=\sqrt{9}$

The radius is 3

3 0

3 years ago

A) y B) y>x<br> C) y+x = 1<br> D) y/x = 1

Bond [772]

Answer:

The answer should be C

6 0

2 years ago