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serg [7]
3 years ago
10

Please help me as soon as possible.

Mathematics
1 answer:
IrinaVladis [17]3 years ago
5 0

\begin{array}{llll} x~-2y=-13\\ 5x+2y=-17\\ \cline{1-1} 6x+0y=-30 \end{array}\qquad \implies 6x=-30\implies x=\cfrac{-30}{6}\implies x=-5 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting on the 1st equation}}{(-5)-2y=-13\implies }-2y=-8\implies y = \cfrac{-8}{-2}\implies y = 4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (-5~~,~~4)~\hfill

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Graph the solution set for the inequality z-4≤3
OleMash [197]

Answer:

  see below

Step-by-step explanation:

Add 4 to find the solution:

  z ≤ 7

The value 7 is included in the solution set, so there will be a solid dot at that point. Numbers less than 7 are also included in the solution set, so the number line will be shaded to the left of that solid dot.

6 0
3 years ago
Gabby received change worth $2.10. She received 3 more dimes than nickels and 4 less quarters than nickels. How many of each kin
xz_007 [3.2K]

Answer:

Gabby received

7 nickels

10 dimes

3 quarters

Step-by-step explanation:

Let

x----> the number of dimes

y----> the number of nickels

z---> the number of quarters

Remember that

1 dime=$0.10

1 nickel=$0.05

1 quarter=$0.25

we know that

0.10x+0.05y+0.25z=2.10 ------> equation A

x=y+3-----> equation B

z=y-4 -----> equation C

substitute equation B and equation C in equation A and solve for y

0.10(y+3)+0.05y+0.25(y-4)=2.10

0.10y+0.30+0.05y+0.25y-1=2.10

0.40y=2.10-0.30+1

0.40y=2.80

y=7 nickels

<em>Find the value of x</em>

x=y+3 -----> x=7+3=10 dimes

<em>Find the value of z</em>

z=y-4 -----> z=7-4=3 quarters

therefore

Gabby received

7 nickels

10 dimes

3 quarters

6 0
3 years ago
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3 years ago
What is the diameter of a cone with height 8 m and volume 150 m3 ? (1 point 7.5 m 15 m?
Hitman42 [59]
This is the concept of volume of solid materials, we are required to find the diameter of cone with height 8 and volume 150 m^3.
volume of cone is given by;V=1/3 (pi*r^2*h)
making r^2 the subject we get;
V/(pi*h)=r^2
inserting the values in our formula we get:
150/(pi*8)=r^2
r^2=5.97
thus;
r=sqrt(5.97)=2.44
But ;
diameter=2*radius
thus
diameter=2.44*2
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3 years ago
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