How would I solve
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Answer:
The answer is below
Step-by-step explanation:
From the image, we can see that DC is parallel to AB.
Step 1:
Alternate interior angles are angles formed at the inner corners of intersection on opposite sides of transversal when two parallel lines are intersected by a transversal.
Since Line AB is parallel to line DC and cut by transversal DB. So angles CDB and ABD are alternate interior angles and must be congruent.
Step 2:
DB ≅ BD (reflexive property of congruence)
Step 3:
∠A = ∠C = 90° (right angles, given). But to prove that both triangles are congruent, the correct step 3 is:
Since, ∠A = ∠C = 90° and angles CDB and ABD are congruent. This means that the third angles in the both triangles are also congruent. Hence, angle ADB and CBD are must be congruent.
Step 4:
BD = DB, angles CDB and ABD are congruent, angle ADB and CBD are congruent.
Therefore, By the Angle-Side-Angle Triangle Congruence Theorem, triangle BCD is congruent to triangle DAB .
