There ar 5 in nitrogen, 20 in hydrogen, and 5 in chlorine. In all that’s 30 compounds.
It would be 100%. As you can see in my punnet square, there are no boxes with ww, which means that ll of the flies would have curled wings. (this is because you have to have two recessive genes for that gene to show)
So it would be
A. 100%
Answer:
D. Nitrogen-14 has 7 electrons, 7 protons, 7 neutrons nitrogen-15 has 7 electrons, 7 protons, and 8 neutrons
Explanation:
In an atom, number of electrons is equal to the number of protons. And the number of neutrons is equal to the difference between the mass number of the atom and the atomic number. For Nitrogen 14, electron is 7, proton is also 7 as number of electrons and number of protons are equal. So, the neutron will be 14-7= 7. For Nitrogen 15, electron number is 7 so proton number will be also 7. Neutron number for nitrogen 15 will be 15-7= 8. That's why the answer is option number 4.
Lipids are NOT made of nucleotides. Nucleotides are the building block for nucleic acid, if that answers your question.
Answer:
c. 1:2:1
The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.
Explanation:
If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:
- RR- red
- ww - white
- Rw - pink
If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).
<u>From this cross the expected ratios are:</u>
- 1/4 RR (red)
- 2/4 Rw (pink)
- 1/4 ww (white)
So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.
<h3><u>Chi square test</u></h3>
<u>The observed frequencies were:</u>
Total 150
<u>The expected frequencies for our null hypothesis are:</u>
- 1/4 x 150 = 37.5 Red
- 2/4 x 150 = 75 Pink
- 1/4 x 150 = 37.5 white
The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.
If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991
Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.