Ask question

Ask question

All categories

2 years ago

15

Write the equation of the line that passes through the points (3, 1) and (9,-3)

1 answer:

Rudiy272 years ago

3 0

Answer:

y = -2/3 + 3

Step-by-step explanation:

y2 - y1 / x2 - x1

-3 - 1 / 9 - 3

-4 / 6

-2/3

y = -2/3x + b

1 = -2/3(3) + b

1 = -2 + b

3 = b

y = -2/3 + 3

You might be interested in

Does anyone know how to do these word problems?

Alex17521 [72]

What is your grade level and which curriculum are you using?

4 0

3 years ago

Which statement best describes the relationship between storage space and number of music files?

Rina8888 [55]

Answer:

As the number of files increases, the storage space used increases.

7 0

3 years ago

PLEASE HELP! find the inverse matrix

Sauron [17]

Answer:

see explanation

Step-by-step explanation:

The inverse of a matrix A = $\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]$ is

$A^{-1}$ = $\frac{1}{ad-bc}$ $\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]$

If ad - bc = 0 then the matrix has no inverse

A = $\left[\begin{array}{ccc}11&-5\\3&-1\\\end{array}\right]$

ad - bc = (11 × - 1) - (- 5 × 3) = - 11 - (- 15) = - 11 + 15 = 4 , then

$A^{-1}$ = $\frac{1}{4}$ $\left[\begin{array}{ccc}-1&3\\-5&11\\\end{array}\right]$ = $\left[\begin{array}{ccc}-0.25&0.75\\-1.25&2.75\\\end{array}\right]$

3 0

3 years ago

Read 2 more answers

_________times_________=63<br> using numbers 2 through 11<br> will give Brainlist

SVEN [57.7K]

Answer:

7 times 9 :)

Step-by-step explanation:

3 0

3 years ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

3 years ago