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Alla [95]
3 years ago
11

Help me pleaseeeeeeeee

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

(4+q)3

Step-by-step explanation:

I think this is it if not Im sorry

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1) -3(5x+2y=-3)⇒ -15x-6y=9
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2) -9x/-9=27/-9 ⇒ x=-3 

3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6

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Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em> 

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If a publisher of nontechnical books takes great pains to ensure that its books are free of typos, so that the probability of an
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