Answer: 294√3
Explanation:
1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a
2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.
3) Then you can use Pythagorean theorem fo find a:
14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3
4) Therefore, the area of one triangle is: 14 × 7√3  / 2 = 49√3
5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
        
             
        
        
        
Answer:
Step-by-step explanation:
The stuff that is yellow is the answer!
 
        
             
        
        
        
Answer:
615.44cm
Step by Step Answer:
A=πr^{2}=π·14^{2}≈615.75216
 
        
             
        
        
        
To determine the degree of a polynomial, you look at every term:
- if the term involves only one variable, the degree of that term is the exponent of the variable
 - if the term involves more than one variable, the degree of that term is the sum of the exponents of the variables.
 
So, for example, the degree of 
 is 55, while the degree of 
 is 
Finally, the term of the degree of the polynomial is the highest degree among its terms.
So, 
 is a degree 2 polynomial (although it only has one term)
similarly, 
 is a degree 3 polynomial: the first two terms have degree 3, because they have exponents 2 and 1.
 
        
                    
             
        
        
        
Answer:
Volume: 2000 cm^3     Surface Area: 1360cm^2
Step-by-step explanation:
Ok, so we know the formula for volume is length x width x height, so we can substitute in the numbers given, so we end up with:
25 x 4 x 20
when we multiply them together, we get: 
2000cm^3. That's the volume.
The formula for Surface Area is: 
S.A.=2(lw+wh+lh) . Now we substitute in the numbers given
S.A.=2( (25 x 4)+(4 x 20)+(25 x 20)) . Then we add and multiply, so we get:
S.A. = 1360cm^2
The Surface Area is 1360cm^2.
Hope this helped, sorry if I was wrong somewhere!
~Mschmindy