Find the attached question.

Mathematics

1 answer:

inessss [21]2 years ago

5 0

p=70°

q=32°

r=38°

Answer:

Solution given:

r=38°[inscribed angle on a same arc are equal]

p=½*140°=70°[inscribed angle is half of the central angle]

<OBA=38°[base angle of isosceles triangle]

again

<C=<B[inscribed angle is half of the central angle]

70°=<OBA+q

70°=38°+q

q=70°-38°

q=32°

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i) $2 - 1.64 \frac{0.1}{\sqrt{16}}= 1.959$

$2 + 1.64 \frac{0.1}{\sqrt{16}}= 2.041$

So then the 90% confidence interval is given by (1.959, 2.041)

ii) Figure attached

iii) $ME= 1.64 *\frac{0.1}{\sqrt{16}}= 0.041$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}}$ (1)

And for a 90% of confidence the significance is given by $\alpha=1-0.9=0.1$ , and $\frac{\alpha}{2}=0.05$ . Since we know the population standard deviation we can calculate the critical value $z_{0.05}= \pm 1.64$